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MAVERICK [17]
3 years ago
12

Find the annual interest rate. I= $50 P= $625 t= 4 years

Mathematics
1 answer:
kolezko [41]3 years ago
8 0
$50 = $625 (r)(4), so r =   50 / (4*625) =  0.02.  This is 2% annually.
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Which inequality is shown in this graph
Katena32 [7]

ANSWER

y \leqslant   - 2x - 2

EXPLANATION

The boundary line passes through (-2,2) and (0,-2).

The slope of this line is

m =  \frac{ - 2 - 2}{0 -  - 2}

m =  \frac{ - 4}{2}  =  - 2

The y-intercept is , c=-2.

The slope-intercept form of this line is given by;

y = mx + c

We substitute values to obtain;

y =  - 2x - 2

Since the lower half-plane is shaded the required inequality is

y \leqslant   - 2x - 2

7 0
3 years ago
3w-4z=8<br> 2w+3z=-6 solve
marissa [1.9K]

Answer:

W = 0

Z = -2

Step-by-step explanation:

While simplyfying the equation, i noticed that one is 24 and the other is -24, which meant that one value is non existent, and after i found out that w = 0 imputing the reslut made that easier

4 0
3 years ago
I need help on the second one
dlinn [17]
It would be reproduction
3 0
3 years ago
Multiply (3x2-4x+5)(x2-3x+2)
Iteru [2.4K]

So with this, you can rewrite the equation as: (3x^2\times x^2)+(3x^2\times -3x)+(3x^2\times 2)+(-4x\times x^2)+(-4x\times -3x)+(-4x\times 2)+(5\times x^2)+(5\times -3x)+(5\times 2)

Firstly, solve the multiplication: 3x^4+(-9x^3)+6x^2+(-4x^3)+12x^2+(-8x)+5x^2+(-15x)+10

Next, combine like terms, and <u>your answer will be: 3x^4-13x^3+23x^2-23x+10</u>

7 0
3 years ago
The temperature of a liquid in an experiment starts at 0 degrees. The temperature of the liquid changes at a rate of -0.2 per mi
Ilia_Sergeevich [38]

Initial temperature of the liquid = 0 degrees.

Rate of changes of liquid temperature = -0.2 per minute.

Rate of change also represents slope of a linear function.

We know, slope-intercept form of a linear equation

y=mx+b, where m is the slope (rate of change) and b is y-intercept(initial temprature).

With respect to given problem, y represents temperature of a liquid after x number of minutes.

According to given problem, slope(rate of change) = -0.2 per minute and y-intercept(initial temprature)=0.

Plugging values of m and b in the above slope-intercept form of a linear equation.We get,

y=-0.2x+0

or y=-0.2x.

Final temprature is given -14.6 degrees and we need to find time when temprature reach -14.6 degrees.

As y represents temperature of a liquid , we need to plug y=-14.6 in above equation.

We get,

-14.6=-0.2x.

Dividing both sides by -0.2.

-14.6/-0.2=-0.2x/-0.2

x=73.

We got 73 minutes.

73 minutes can be convert in hours.

We have 60 minutes in an hour.

Therefore, 73 = 60+13.

So, 1 hour and 13 minutes will it for the liquid to reach -14.6 degrees.

In minutes answer is 73 minutes.

3 0
3 years ago
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