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ehidna [41]
2 years ago
12

Help pls

Mathematics
1 answer:
sveta [45]2 years ago
7 0

5 year olds and younger, 0c

5years to 12 years, 10c

12 to 18 years, 25c

Adules 35, 35c

C is for the amount of people

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Drag an expression to the box to create an equation with no solutions.
Anon25 [30]

Answer:

C

Step-by-step explanation:

4x + 3 = x + 3x + 5

4x + 3 = 4x + 5 //-4x on both sides

3 = 5 //Since the statement is false, it's no solution.

If, it had 3 = 3 or any number n = n, the solution would be infinite. But, if x is equal to any number n, x=n, it would have only one solution.

//Hope it helps

4 0
3 years ago
MARK AS BRAINLIESTT
Lelu [443]

Answer

 B) x + 20 ≥ 50

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Help Me with this question please​
artcher [175]

Answer:

22

Step-by-step explanation:

The abs of y is 29 because 29 is positive

51 - 29 = 22

4 0
3 years ago
Read 2 more answers
What the slope of(7,3) (6,-2)​
antoniya [11.8K]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

slope =  \frac{ - 2 - 3}{6 - 7}  \\

slope =  \frac{ - 5}{ - 1}  \\

slope = 5

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6 0
2 years ago
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
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