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alexandr402 [8]
3 years ago
12

What does 3+3 (a) simplify to when a=5

Mathematics
2 answers:
pav-90 [236]3 years ago
4 0

3 + 3 \times 5 = 18
KiRa [710]3 years ago
3 0
3 + 3(5) = 3 + 15 = 18
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the length of a rectangle is 5ft longer than it's width. if the perimeter of the rectangle is 34ft, find it's area?
galina1969 [7]
2X + (2X+10)= 34

Width is 6, Length is 11

6 x 11 is 66

Area is 66
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3 years ago
y = 2x squared + 5x -3 can be written in the form y= 2( x+a) squared + b . Find the value of a and the value of b.
Elan Coil [88]

General vertex form:

y = m(x − a)² + b  \: with  \: vertex \:  at \:  (a, b)

Given :

y = 2x² + 5x  - 3

Extract "spread factor" m

y = 2( x² +  \frac{5}{2} x) - 3

Complete the square

y = 2(x²  +  \frac{5}{2}x + ( \frac{5}{4})²) - 3

- 2( \frac{5}{4})²

Write as a squared binomial and simplify the constant

y = 2(x +  \frac{5}{4})² - 6 \frac{1}{8}

Re-write to match signs of standard general form:

y = 2(x - ( -  \frac{5}{4}))² \:  + ( - 6 \frac{1}{8})

3 0
2 years ago
What is the value of x in this figure?
Arte-miy333 [17]

Answer:

x=48°

Step-by-step explanation:

We two lines cross over each other, making four angles, the angles opposite each other are equal. They're called vertically opposite angles.

8 0
2 years ago
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A student performed the composition rx Ro 90 on figure A. Evaluate the students completion of the composition.
kotegsom [21]
First: The student rotated the figure 90° clockwise.
Second: The student reflected across the x-axis.

Answer: Option C. <span>The student rotated the figure 90° clockwise rather than 90° counterclockwise.</span>

7 0
3 years ago
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And, S2
dangina [55]

<u>Correct Question</u>

In the table shown, the sum of each row is shown to the right of the row and the sum of each column is shown below the column. What is the value of L?

\left|\begin{array}{c|c|c|c}-&-&-&-\\J&K&J&5\\K&K&L&13\\L&J&L&15\\-&-&-&-\\11&7&15\end{array}\right

Answer:

L=7

Step-by-step explanation:

From the first row: 2J+K=5

Therefore: K=5-2J

From the second column, 2K+J=7

Substitute K derived above into 2K+J=7

2K+J=7

2(5-2J)+J=7

10-4J+J=7

-3J=7-10

-3J=-3

J=1

Recall: K=5-2J

K=5-2(1)=3

K=3

From the third column, J+2L=15

1+2L=15

2L=15-1=14

L=7

Therefore, the value of L=7

CHECK:

\left|\begin{array}{c|c|c|c}-&-&-&-\\1&3&1&5\\3&3&7&13\\7&1&7&15\\-&-&-&-\\11&7&15\end{array}\right

4 0
3 years ago
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