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olasank [31]
3 years ago
13

What is the simplified expression for the expression below?

Mathematics
2 answers:
Alika [10]3 years ago
4 0
We have the expression 4(x + 8) + 5(x - 3).
First, expand the parentheses by using the distributive property.

4(x + 8) + 5(x - 3) = 4x + 32 + 5x - 15

Now combine like terms.

4x + 32 + 5x - 15 = 9x + 17

So, C 9x + 17 is the answer.
Ierofanga [76]3 years ago
3 0

Answer:

c) 9x+17

Step-by-step explanation:

i did it on edge

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PLEASE HELP ILL MARK THE FIRST RIGHT ANSWER AS BRAINIEST
Bas_tet [7]

Answer:

26 rows

Step-by-step explanation:

126/5=25.2

there no such thing as a .2 of a row so you have to add one more

25+1=26 rows

7 0
4 years ago
Read 2 more answers
Can you please answer the question?
Roman55 [17]

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}

\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }

\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}

\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}

\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}

\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}

\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}

\tan \alpha + 1 + \cot \alpha

\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1

\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1

\frac{1}{\cos \alpha \cdot \sin \alpha} + 1

\sec \alpha \cdot \csc \alpha + 1

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0
2 years ago
There are 14 books on a shelf. 5 of these books are new.
GuDViN [60]
A)5:9
b)14:5
the are the answers 

7 0
3 years ago
What is the equation if the line slope is 2/3 and the y-intercept is -3
lora16 [44]
<h2>The required equation of line is 2x - 3y - 9 = 0.</h2>

Step-by-step explanation:

Here, slope(m) = \dfrac{2}{3} and y - intercept(c) = -3

To find, the required equation of line = ?

We know that,

The equation of a line with slope m and y-intercept c is given by

y = mx + c

∴ The required equation of line

y = \dfrac{2}{3}x + (- 3)

⇒ y = \dfrac{2}{3}x - 3

⇒ y + 3 = \dfrac{2}{3}x

⇒ 3(y + 3) = 2x

⇒ 3y + 9 = 2x

⇒ 2x - 3y - 9 = 0

Thus, the required equation of line is 2x - 3y - 9 = 0.

7 0
4 years ago
Describe the graph of the Celsius-Fahrenheit relationship
White raven [17]

Using linear function concepts, the graph of the Celsius-Fahrenheit relationship is linear with an intercept of 32 and slope of 1.8.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

From the table, we have that:

  • When the input is of 0, the output is of 32, hence the intercept is of 32.
  • When the input changes by 10, the output changes by 18, hence the slope is of 18/10 = 1.8.

Thus, the graph of the Celsius-Fahrenheit relationship is linear with an intercept of 32 and slope of 1.8.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

6 0
2 years ago
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