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harkovskaia [24]
3 years ago
10

In a science test Jamie solved 42 correct and 18 incorrect answers what is the percentage of correct questions

Mathematics
2 answers:
Mkey [24]3 years ago
6 0
The percentage is 2.3
snow_lady [41]3 years ago
6 0
42 - 18 = 24
24 people had correct answers
24/42 = 57%
57%, Hope this helps!
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Given that y = } 1/2(x1 + x2)c, what is y when X 1 = 3, X2 = 5, and c = 6?
vampirchik [111]

Answer:

24

Step-by-step explanation:

1/2(x1+x2)c x1=3 , x2=5 , c=6

:- 1/2(3+5)6 ( BODMAS)

:- 1/2(8)6 divide 8 by 1/2

:- (4)6 multiply both of them and the result = 24

7 0
3 years ago
Marta conducts emissions inspections on cars. She finds that 8 percent of the cars fail the inspection. Let X be the number of c
exis [7]

Answer:

mean - 12.5

SD - 12.0

Step-by-step explanation:

6 0
3 years ago
If y = 2x2 – 4x, what is the value of y when x equals 5. <br> A.10 <br> B.30 <br> C.80 <br> D.480
Ainat [17]

Answer:

The value of y in the given equation is B. 30.

Step-by-step explanation:

y = 2x² - 4x             x = 5

y = 2(5)² - 4(5)        Plug 5 in for x

y = 2(25) - 20         Square 5 and multiply 4 by 5

y = 50 - 20             Multiply 2 by 25

y = 30

Hope this helps,

❤<em>A.W.E.</em><u><em>S.W.A.N.</em></u>❤

6 0
3 years ago
Caroline has 16 marbles 1/8 of them are blue how many of Caroline's marbles are blue
DedPeter [7]
2 . You have to divide 16 by 8. you get 2 . Hoped that helped
4 0
3 years ago
Read 2 more answers
Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!
Rudiy27

Use these equations when converting polar equations to parametric equations:

x=r\cos\theta

y=r\sin\theta

We know that r=5\theta, so substitute that into both equations for x and y.

x=5\theta\cos\theta

y=5\theta\sin\theta

Now, replace \theta with any variable that you want to represent the parametric equations in. I'll use the standard variable, t

x=5t\cos t

y=5t\sin t

Thus, r=5\theta represented in parametric form is:

(x,y)=(5t\cos t, 5t \sin t)

Let me know if you need any clarifications, thanks!

~ Padoru

4 0
3 years ago
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