Question

If cos0 =1/3 then sin0=?

Answer 1

Answer:

sin θ = +/- (2√2)/3

Step-by-step explanation:

cos θ  = 1/3

cos²θ  + sin²θ  = 1

(1/3)² + sin²θ  = 1

sin²θ  = 1 - 1/9

√(sin²θ) = +/-√(8/9)

sin θ = +/- (2√2)/3