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Mazyrski [523]
3 years ago
7

WORTH 20 POINTS!! HELP!!!

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
Expenditures are negatives do I'd use -42.50
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Find the quotient of 2.6 divided by 0.04
lara31 [8.8K]

Answer:

65

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
22. f(x) is stretched horizontally by a factor of 2 and reflected across the x-axis. Which choice shows the correct representati
goblinko [34]

Answer:

A. -f(1/2 x)

Step-by-step explanation:

Reflextion about the x-axis is

f(x) -> -f(x)

and horizontal dilation is

f(x) -> f(-x/b) where b is the factor of dilation.

so the proper answwer is

A. -f(1/2 x)

6 0
3 years ago
1.
Bad White [126]

first polygon

ext. angle=180°-120°

=60°

ext \: ang =  \frac{360}{n}

n=360°/60°

n=6

second polygon

n=2(6)=12

ext. ang= 360°/n = 360°/12° = 30°

int. ang = 180°-30°= 150°

answer is C

6 0
4 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
You decide to go to the candy store in the mall. You arrive at the store with $25 and then purchase 3 candy bars. You then buy a
Yuri [45]

Answer:

<h2> The cost of a candy is $1.25</h2>

Step-by-step explanation:

given the total amount at hand is $25

let the price of  candy be x

then the cost of 3 candy will  be 3x

the cost of a candy snake is $12.50.

balance at hand after the end of buying $8.75

the total expenses summed up must equal the initial amount at hand which is $25

the expression for the scenario is 3x+12.5+8.75=25

3x+21.25=25

3x=25-21.25

3x=3.75

x=3.75/3

x=$1.25

The cost of a candy is $1.25

4 0
3 years ago
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