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Ivanshal [37]
3 years ago
14

The ________ of an angle is a segment or a ray that passes through the vertex of an angle and splits it into two congruent angle

s.
Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
Bisector is the correct answer  <span />
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The sum of n 2 more than n
Lena [83]
N+2 would be the correct answer... i think!!!!!!!!!!!!

Hope i helped!!!!!!!!

4 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin
yarga [219]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=3\\ k=-7 \end{cases}\implies y=a(x-3)^2-7\qquad \textit{we also know that} \begin{cases} x=1\\ y=-10 \end{cases} \\\\\\ -10=a(1-3)^2-7\implies -3=a(-2)^2\implies -3=4a\implies -\cfrac{3}{4}=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-\cfrac{3}{4}(x-3)^2-7~\hfill

5 0
1 year ago
Find the output value of the function. f(x)=5x-8 for f(7)
Molodets [167]

Answer:

27

Step-by-step explanation:

f(x) = 5x - 8

f(7) = 5(7) - 8 = 27

3 0
3 years ago
Read 2 more answers
Please help me Solve -2a -5&gt;3
worty [1.4K]

Answer:

a < -4

Step-by-step explanation:

Step 1: Write out inequality

-2a - 5 > 3

Step 2: Add 5 to both sides

-2a > 8

Step 3: Divide both sides by -2

a < -4

Here, we can see that any value of <em>a </em>less than -4 works. So <em>a</em> could be -124 or -5, or even -1271293587923857 and it would work.

4 0
2 years ago
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