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Hitman42 [59]
3 years ago
5

Clicking on this will minimize all open windows.

Computers and Technology
2 answers:
grin007 [14]3 years ago
8 0

hey bud it's paps here to help ya out

Right-click on the task-bar. The task-bar is the bar at the bottom of the screen where programs can be accessed and displayed.

Click on the option 'Show the desktop'. This should minimize all open windows and show the desktop.

Right-click again to bring your windows back to view.

s&p

vfiekz [6]3 years ago
4 0
I believe it is the the Show Desktop Icon.
Hope this helps! <3
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Name all the keys of the home row.
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A loop decision point for an algorithm consists of three features: an initial value, a set of actions to be performed, and a(n)
pychu [463]

Answer:

Option c is the correct answer for the above question.

Explanation:

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The above question also states about the loop in which first and second points are given then the third point is necessary to complete the sentence which is states in option c. Hence the option c is correct while the other is not because--

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write a program to evaluate the following postfix expression. the value of each variable must be asked from the user during the
ikadub [295]

In this exercise we have to use the knowledge of computational language in C++ to write a code that program to evaluate the following postfix expression. the value of each variable must be asked from the user during the execution time.

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// CREATED A </em><em>CLASS </em><em>STACK</em>

<em>class Stack</em>

<em>{</em>

<em>public:</em>

<em> int top;</em>

<em> unsigned sz;</em>

<em> int* ar;</em>

<em>};</em>

<em>// VARIOUS STACK </em><em>FUNCTIONS</em>

<em>Stack* makeStack( unsigned sz )</em>

<em>{</em>

<em> Stack* stack = new Stack();</em>

<em> // BASE </em><em>CONDITION</em>

<em> if (!stack) return NULL;</em>

<em> stack->top = -1;</em>

<em> stack->sz = sz;</em>

<em> stack->ar = new int[(stack->sz * sizeof(int))];</em>

<em> if (!stack->ar) return NULL;</em>

<em> // RETURNING THE STACK</em>

<em> return stack;</em>

<em>}</em>

<em>// CHECKING IF THE STACK IS </em><em>EMPTY</em>

<em>int isEmpty(Stack* stack)</em>

<em>{</em>

<em> return stack->top == -1 ;</em>

<em>}</em>

<em>// CHECKING THE TOP OF THE STACK</em>

<em>int whatAtTop(Stack* stack)</em>

<em>{</em>

<em> return stack->ar[stack->top];</em>

<em>}</em>

<em>// </em><em>POPPING </em><em>OUT OF A STACK</em>

<em>int pop(Stack* stack)</em>

<em>{</em>

<em> if (!isEmpty(stack))</em>

<em>  return stack->ar[stack->top--] ;</em>

<em> return '$';</em>

<em>}</em>

<em>// PUSHING IN THE STACK</em>

<em>void push(Stack* stack, int op)</em>

<em>{</em>

<em> stack->ar[++stack->top] = op;</em>

<em>}</em>

<em>// EVALUATING </em><em>POSTFIX </em><em>STARTS HERE</em>

<em>int postfixEvaluator(string res)</em>

<em>{</em>

<em> // CREATING STACK</em>

<em> Stack* stack = makeStack(res.length());</em>

<em> int i;</em>

<em> // BASE </em><em>CONDITION</em>

<em> if (!stack) return -1;</em>

<em> for (i = 0; res[i]; ++i)</em>

<em> {</em>

<em>  // CHECK FOR SPACES</em>

<em>  if (res[i] == ' ')continue;</em>

<em>  // CHECK FOR THE DIGIT</em>

<em>  else if (isdigit(res[i]))</em>

<em>  {</em>

<em>   int N = 0;</em>

<em>   // EXTRACT THE </em><em>NUMBER </em><em>OUT OF STACK</em>

<em>   while (isdigit(res[i]))</em>

<em>   {</em>

<em>    N = N * 10 + (int)(res[i] - '0');</em>

<em>    i++;</em>

<em>   }</em>

<em>   i--;</em>

<em>   // </em><em>PUSH </em><em>THE NUMBER IN STACK</em>

<em>   push(stack, N);</em>

<em>  }</em>

<em>  // POPPING AND </em><em>ARITHMETIC </em><em>OPERATIONS</em>

<em>  else</em>

<em>  {</em>

<em>   int pos1 = pop(stack);</em>

<em>   int pos2 = pop(stack);</em>

<em>   switch (res[i])</em>

<em>   {</em>

<em>   case '+': push(stack, pos2 + pos1); break;</em>

<em>   case '-': push(stack, pos2 - pos1); break;</em>

<em>   case '*': push(stack, pos2 * pos1); break;</em>

<em>   case '/': push(stack, pos2 / pos1); break;</em>

<em>   }</em>

<em>  }</em>

<em> }</em>

<em> return pop(stack);</em>

<em>}</em>

<em>// MAIN CODE</em>

<em>int main()</em>

<em>{</em>

<em> string tes;</em>

<em> getline(cin, tes);</em>

<em> string tmp = "";</em>

<em> string res = "";</em>

<em> for (int i = 0; i < tes.length(); i++) {</em>

<em>  if (tes[i] <= 'z' and tes[i] >= 'a') {</em>

<em>   tmp += tes[i];</em>

<em>  } else if (tes[i] == ' ' and (tes[i - 1] <= 'z' and tes[i - 1] >= 'a')) {</em>

<em>   cout << "Enter the value of " << tmp << ": ";</em>

<em>   int x; cin >> x;</em>

<em>   res += (to_string(x));</em>

<em>   res += ' ';</em>

<em>   tmp = "";</em>

<em>  } else {</em>

<em>   res += tes[i];</em>

<em>  }</em>

<em> }</em>

<em> cout << "\nThe postfix expression is : " << res;</em>

<em> cout << "\nThe result is : " << postfixEvaluator(res);</em>

<em> return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

8 0
1 year ago
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