First addition, then division
Answer:
a) Generate a new public and private key
Explanation:
You encrypt a message using the recipient's public key and the recipient decrypts the message using his own private key. Only the public key can be known by an external agent. The private key is for the individual and is not expected to be shared. In the event that the recipient cannot decrypt the message, it is unsafe to send one's private key to him. He does not even need one's private key to decrypt the message, he needs his own private key.
The best thing to do is to generate another means of security by generating new public and private key so that the sender encrypts the message with the new public key and the receiver decrypts it using his new private key.
Option B is wrong because, if the encryption is removed, the aim, which is to secure the message from intruders is not achieved.
Answer:
Select the Zoom tool, and then do any of the following:
<h2>#1. </h2>
Click and hold in the image to zoom in. Press Alt (Windows) or Option (Mac OS) to zoom out.
<h2>#2!</h2>
In the options bar, select Scrubby Zoom. Then drag to the left in the image to zoom out, or to the right to zoom in.
<h2>psst! pls, brailiest!</h2>
Answer:
a) AL will contains 0011 1100
Explanation:
In assembly language, shifting bits in registers is a common and important practice. One of the shifting operations is the SHR AL, x where the x specifies that the bits be shifted to the right by x places.
SHR AL, 2 therefore means that the bits contained in the AL should be shifted to the right by two (2) places.
For example, if the AL contains binary 1000 1111, the SHR AL, 2 operation will cause the following to happen
Original bit => | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 |
Shift once to the right => | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | (0) |
Shift once to the right => | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 1 | (0) | (0) |
Notice;
(i) that there are two shifts - one at a time.
(ii) that the bits in bold face are the bits in the AL after the shift. Those that in regular face are those in the carry flag.
(iii) that the new bits added to the AL after a shift are the ones in bracket. They are always set to 0.
