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hodyreva [135]
3 years ago
13

Which principle of design does a designer apply when they create rhythmic movement in a garment by using recurring pleats or det

ails
Computers and Technology
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

Repetition, and regular rhythm

Explanation:

Its certainly repetition method, and repetition method is of three types which are repetition, pattern and rhythm.

Remember repetition can be boring at times as we need to read same thing again and again. However, repetition sometimes can be good like the one we are referring to, and the other one can be like placing the logo or menu at same place in all web page. And its since it creates a habit in us for reading the web pages, And hence we can understand faster, and it looks please to our eyes hence as well.  

You might be interested in
1. Bluetooth
Elza [17]

Complete Question:

1. A wireless technology standard for exchanging data over short distances

2. A particular brand of mobile phone/PDA

3. A network that operates over a limited distance, usually for one or a few users

1. Bluetooth

2. PAN

3. Blackberry

Answer:

1. Bluetooth 2. Blackberry . 3. PAN

Explanation:

1. Bluetooth is a wireless technology standard, used in order to exchange data between mobile devices, like smartphones, tablets, headsets, wearables, over short distances in a one-to-one fashion (which means that it is not possible to build a network based in Bluetooth).

2. Blackberry is a brand of mobile phones/PDAs, very popular a decade ago, because it was the first one to allow mobile users to access e-mails and messages from anywhere, at any time.

3. PAN (Personal Area Network) is an ad-hoc network that it is only available for data exchange at a very short distance, within the reach of a person, i.e. a few meters as a maximum.

It is thought to allow someone to interact with his nearest environment (laptop, tablet, PDA) and it can be wireless (like Bluetooth) or wired (via USB cables).

4 0
4 years ago
In JAVA please:
blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;  

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

 if (keysList[i]>50){

  System.out.println(itemsList[i] + " ");  }  }

System.out.println("");

}

}

Explanation:

I will explain the whole program flow.

  • There are two arrays here
  • keysList and itemsList
  • The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second  position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

  • The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second  position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

  • The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
  • Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
  • So the program control enters the body of the loop.
  • In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
  • In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
  • So the output of the above program is:

72

54

5 0
3 years ago
To create a multiple-table form based on the âmanyâ table, tap or click the ____ button on the create tab to create a form in la
Archy [21]
Click on the blank form button. 
3 0
3 years ago
What is a collection of computing resources that are elastic and highly virtualized?
In-s [12.5K]

Answer:

private cloud

Explanation:

I just know

5 0
3 years ago
HAVE A GOOD WEEK OFF PPL
dexar [7]

Answer:

thanks you too mah dude! :)

Explanation:

7 0
3 years ago
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