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Vika [28.1K]
4 years ago
15

Whats a3 +b2 ×a3+b5 i need to know

Mathematics
1 answer:
Oksanka [162]4 years ago
4 0

The answer is a^6 b^7a^6b^7

You have to add the exponents.

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Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is
professor190 [17]
Ok, here we go.  Pay attention.  The formula for the arc length is AL= \int\limits^b_a { \sqrt{1+( \frac{dy}{dx})^2 } } \, dx.  That means that to use that formula we have to find the derivative of the function and square it.  Our function is y = 4x-5, so y'=4.  Our formula now, filled in accordingly, is AL= \int\limits^2_1 { \sqrt{1+4^2} } \, dx (that 1 is supposed to be negative; not sure if it is til I post the final answer).  After the simplification we have the integral from -1 to 2 of \sqrt{17}.  Integrating that we have AL= \sqrt{17}x from -1 to 2.  2 \sqrt{17}-(-1 \sqrt{17} ) gives us 3 \sqrt{17}.  Now we need to do the distance formula with this.  But we need 2 coordinates for that.  Our bounds are x=-1 and x=2.  We will fill those x values in to the function and solve for y.  When x = -1, y=4(-1)-5 and y = -9.  So the point is (-1, -9).  Doing the same with x = 2, y=4(2)-5 and y = 3.  So the point is (2, 3).  Use those in the distance formula accordingly: d= \sqrt{(2-(-1))^2+(3-(-9))^2} which simplifies to d= \sqrt{9+144}= \sqrt{153}.  The square root of 153 can be simplified into the square root of 9*17.  Pulling out the perfect square of 9 as a 3 leaves us with 3 \sqrt{17}.  And there you go!
5 0
3 years ago
A semi-circle sits on top of a rectangle to form the figure below. Find its area and perimeter. Use 3.14 for pi , and round your
gladu [14]
The answer would be perimeter = 10 + 2 pi
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3 0
3 years ago
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Answer:

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3 years ago
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