Answer:
C++.
Explanation:
#include <iostream>
#include <string>
using namespace std;
////////////////////////////////////////////////////////////////////////////
int sumDigits(string alphanumeric) {
if (alphanumeric.length() == 1) {
if ((int(alphanumeric[0]) >= 48) && (int(alphanumeric[0]) <= 57)) {
cout<<int(alphanumeric[0]) - 48<<endl;
return (int(alphanumeric[0]) - 48);
}
else
return 0;
}
else {
if ((int(alphanumeric[0]) >= 48) && (int(alphanumeric[0]) <= 57)) {
cout<<int(alphanumeric[0]) - 48<<endl;
return int(alphanumeric[0]) - 48 + sumDigits(alphanumeric.substr(1, alphanumeric.length()-1));
}
else
return 0 + sumDigits(alphanumeric.substr(1, alphanumeric.length()-1));
}
}
////////////////////////////////////////////////////////////////////////////
int main() {
cout<<"Sum: "<<sumDigits("ab1c2d3e54");
return 0;
}
This code attempts to fuse two strings together. So,
fuse("Apple", "Banana")
would return "ABpapnlaen a"
However, there are a couple of things wrong with this code:
- The for loop is incomplete (probably a copy paste error)
- It is unclear from the code if the array jawaban will overflow if kata1 and kata2 are large (it probably will)
- Biggest problem: the jawaban array is declared on the stack, which means it will be cleaned up when the function returns. So the caller of this function will reference unallocated memory! This is a huge bug!!
Well hypothetically I've seen a lot of cars but like Bentleys Lamborghinis Ferraris and Rolls Royce's but it'll probably hypothetically have to be my mom 2004 Toyota camery
Answer:
Constant
Explanation:
One of the flexibility of worksheet is using cell references to get the value of a cell, this will make the overall formula update itself when cell values are changed, but when using a constant to make computation the formula is not keeping track of the contents of the cells for any change and this will make it a fresh work to get a value based on changed values.
Explanation:
1. the intensities of each color beam
2. -
3. False
4. red
hope it helps!