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Brums [2.3K]
3 years ago
14

Without using any additional variables, and without changing the values of ndays or the elements of the parkingTickets array, wr

ite some code that results in mostTickets containing the largest value found in parkingTickets.
Computers and Technology
1 answer:
dusya [7]3 years ago
7 0

Answer:

Explanation:

mostTickets=0;

for (k=0; k< ndays; k++){

if (parkingTickets[k]>mostTickets) mostTickets=parkingTickets[k];

}

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Just a quick question, how do you set something == to char and int in an if statement (java)
Troyanec [42]

This is the requested code in java.

public class <em>CharTest</em> {

   public static String checkCharacter(String text, int index) {

       if (0 <= index && index <= text.length()) {

           char ch = text.charAt(index);

           if (Character.isLetter(ch)) {

               return ch + " is a letter";

           } else if (Character.isDigit(ch)) {

               return ch + " is a digit";

           } else if (Character.isWhitespace(ch)) {

               return ch + " is a whitespace character";

           } else {

               return ch + " is an unknown type of character";

           }

       } else {

           return "index " + index.toString() + " is out of range";

       } // <em>end if</em>

   } // <em>end function checkChar()</em>

   public static void <em>main</em>(String[] args) {

       // <em>Test the three samples from the specification.</em>

       System.out.println(<em>checkCharacter</em>("happy birthday", 2));

       System.out.println(<em>checkCharacter</em>("happy birthday", 5));

       System.out.println(<em>checkCharacter</em>("happy birthday 2 you", 15));

   } // <em>end function main()</em>

} // <em>end class CharTest</em>

The function <em>checkcharacter</em>(text, index) returns a string value describing the kind of character found at the position in text specified by index; whether it was a letter, digit, whitespace, or an unknown kind of character.

How it does that is to make use of respective functions defined within the Character class in java. That is

  • isLetter(char) returns a bool specifying if the char parameter is a letter.
  • isDigit(char) returns a bool specifying if the char parameter is a digit.
  • isWhitespace(char) returns a bool specifying if the char parameter is a whitespace character.

It calls these functions in an if statement. These else part of the if statement is then executed if the character is neither a <em>letter</em>, <em>digit</em>, or <em>whitespace</em>.

Finally, the function main() calls <em>checkCharacter</em>() three times to test the function and return the results to the console.

Another example of a java program on characters is found in the link below

brainly.com/question/15061607

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schepotkina [342]

Answer:

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Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
3 years ago
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