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olchik [2.2K]
2 years ago
12

HELLLLLLLLPPPPPPPPPPPP HHHHHHHHHEEEEEEEEELLLLLLPPPPPP MEEEEEEEE

Computers and Technology
2 answers:
sladkih [1.3K]2 years ago
8 0

Answer:

c

Explanation:

Salsk061 [2.6K]2 years ago
8 0

Answer:

C. Natural language

Explanation:

this is because the search query uses normal letters and phrases without attaching codes

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kompoz [17]

Answer:

the vampire diareas

Explanation:

7 0
2 years ago
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8.11 LAB: Count characters - functions Write a program whose input is a character and a string, and whose output indicates the n
Shkiper50 [21]

Answer:

#include<iostream>

using namespace std;

int CountCharacters(char userChar, const string inputstr){

   int k = 0;

   int iter = 0;

   for (iter = 0; iter < inputstr.size(); iter++){

       if (inputstr[iter] ==  userChar){

           ++k;        }}

   return k;}

int main(){

   string str;

   char userChar[1];

   cout<<"Char: ";    cin>>userChar;

   cin.ignore();

   cout<<"String: ";   getline(cin, str);

   cout<<CountCharacters(userChar[0],str);

   return 0;}

Explanation:

Written in C++:

The function is defined here:

int CountCharacters(char userChar, const string inputstr){

This initializes a count variable k to 0

   int k = 0;

This initializes an iterating variable iter to 0

   int iter = 0;

This iterates through the characters of the string being passed to the function

   for (iter = 0; iter < inputstr.size(); iter++){

This checks for matching characters

       if (inputstr[iter] ==  userChar){

If found,  k is incremented by 1

           ++k;        }}

This returns the total count

   return k;}

The main begins here

int main(){

This declares a string variable

   string str;

This declares a character variable

   char userChar[1];

This gets input for the character variable

   cout<<"Char: ";    cin>>userChar;

This lets the user get another input

   cin.ignore();

This gets input for the string variable

   cout<<"String: ";   getline(cin, str);

This calls the function and return the count of character in the string

   cout<<CountCharacters(userChar[0],str);

6 0
2 years ago
Given positive integer numinsects, write a while loop that prints that number doubled without reaching 100. follow each number w
hichkok12 [17]
Hi,

the program is as follows
___________________________________________________________


import java.io.*;
class doubleval

  {
     public static void main()throws IOException   
     {

       DataInputStream dt=new DataInputStream(System.in); 

System.out.println("Enter NUMBER WHOSE DOUBLE U WANT TO                                           PRINT");       
            int n=Integer.parseInt(dt.readLine()); 

                  for(int i=n;i<=100;i=2*i)       
                    {           
                         System.out.println(i);       
                            }   
            }
}


           
3 0
2 years ago
Binary is a base-2 number system instead of the decimal (base-10) system we are familiar with. Write a recursive function PrintI
Paladinen [302]

Answer:

In C++:

int PrintInBinary(int num){

if (num == 0)  

 return 0;  

else

 return (num % 2 + 10 * PrintInBinary(num / 2));

}

Explanation:

This defines the PrintInBinary function

int PrintInBinary(int num){

This returns 0 is num is 0 or num has been reduced to 0

<em> if (num == 0)  </em>

<em>  return 0;  </em>

If otherwise, see below for further explanation

<em> else </em>

<em>  return (num % 2 + 10 * PrintInBinary(num / 2)); </em>

}

----------------------------------------------------------------------------------------

num % 2 + 10 * PrintInBinary(num / 2)

The above can be split into:

num % 2 and + 10 * PrintInBinary(num / 2)

Assume num is 35.

num % 2 = 1

10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)

17 will be passed to the function (recursively).

This process will continue until num is 0

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Which of the following guidelines about forwarding e-mail messages is most appropriate?
valentina_108 [34]
The last option: 

Avoid forwarding e-mail messages unless you have permission to do so.
5 0
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