All categories

4 years ago

0.0057 in scientific notation

Mathematics

2 answers:

Gelneren [198K]4 years ago

4 0

Answer:

5.7*10^-3

Step-by-step explanation:

Natasha_Volkova [10]4 years ago

4 0

Answer:

5.7 x10^-3

Step-by-step explanation:

0.0057 = 5.7 x10^-3

there should only one number before the decimal place in the final answer, so move back 3 decimal places, as a result it becomes to the power of three

You might be interested in

A company maintains a fleet of vehicles that consist of both cars and trucks. The miles per gallon realized in the cars follows

sergeinik [125]

Answer:

ii, the mpg for the trucks.

Step-by-step explanation:

A larger standard deviation means more variablilty

8 0

2 years ago

Solve for x<br><br> 1) 3x - 2 = 10

Olegator [25]

Answer: x equals 4 your welcome

8 0

3 years ago

Read 2 more answers

What is the length of the line segment in the x-y plane with end points at (-2,-2) and (2,3)?

diamong [38]

(-2-2)^2+(-2-3)^2=16+25=41 Length is square root of 41

5 0

4 years ago

A rectangular floor is 20 feet long and 16 feet broad. if it is to be paved with squared marbles of same size,find the greatest

asambeis [7]

Answer:

[/tex]

$\Large{\bf{\green{\mathfrak{\dag{\underline{\underline{Given:-}}}}}}}$

[/tex]

6 0

3 years ago

Read 2 more answers

Kevin Horn is the national sales manager for National Textbooks, Inc. He has a sales staff of 40 who visit college professors al

just olya [345]

Answer:

(a) median = 57

(b) Q1=50 Q3=63.5

(c)D1 = 41 D9=67

(d)P33= 51

Step-by-step explanation:

(a) The numbers are arranged in ascending order, and there are even number of calls. So the median will be the average of the middle terms.

middle terms are 55 and 59

Median = $\frac{55+59}{2}$

median= 57

(b) First quarter Q1 = $\frac{1}{4} number of calls$ th

= $\frac{1}{4} *30$ th

= 7.5th

so the first quarter lies in the 7.5th= (7+0.5)th term

So we multiply 0.5 by the difference of the 7th and 8th term

=0.5 *0= 0

Q1 = 50+0=50

Q3= $\frac{3}{4} number of calls$ th

= $\frac{3}{4} *30$ th

=22.5th = (22+0.5)th term

So we multiply 0.5 by the difference of the 22th and 23rd term

= 0.5*1=0.5

Q3= 63+0.5=63.5

(c) First decile (D1) = $\frac{1}{10} number of calls$ th

= $\frac{1}{10} *30$ th

= 3rd term

D1= 41

D9= $\frac{9}{10} number of calls$ th

= $\frac{9}{10} *30$ th

=27th term

D9 = 67

(d) 33rd percentile = $\frac{33}{100} number of calls$ th

= $\frac{33}{100} *30$ th

= 9.9th term = (9 +0.9)th

Multiply 0.9 by the difference between the 9th and tenth term.

= 0.9*0 =0

P33 = 51

8 0

3 years ago