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Alchen [17]
3 years ago
6

4x + 3y = -26 x-3y =-14

Mathematics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

y = 8       x= -16

Step-by-step explanation:

4x+26x = -6y =14

30x = 14

-6y = 14     x = 14- 30

y+= 14-6  

y = 8       x= -16

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Pouvez-vous m'aider s'il vous plaît
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Answer:

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Step-by-step explanation:

6 0
3 years ago
ABC is a right triangle, A is located at the origin, B is the right angle, AB = 12, and BC = 5. Find the coordinates of point C
horsena [70]
If B lies along the positive x-axis, then the coordinate of B is (12, 0). Since the right angle is at B and BC is 5, it means that C is 5 units above B.
Therefore, the coordinate of C is (12, 5)
8 0
3 years ago
Read 2 more answers
1. A right triangle has a hypotenuse of length 10 yd and one leg of length 2 yd.
Aleonysh [2.5K]

Question 1.

The Pythagoras Theorem states that the square of the hypotenuse is equal to the sum of the square of the two legs.

h^2=l_1^2+l_2^2

From the question, the hypotenuse is h=10 yd and one of the legs is 2yd.

This implies that,

10^2=l_1^2+ {2}^{2}

Evaluate the exponents

100=l_1^2+ 4

Subbtract 4 from each side

100 - 4=l_1^2

l_1^2 = 96

l_1=  \sqrt{96}

l_1 =  \sqrt{16 \times 6}

l_1 =  4\sqrt{6}

The correct answer is C

Question 2

We want to solve

{e}^{4x}  = 11

using inverse functions.

The inverse of an exponential function is a logarithmic function.

We take natural log of both sides to get;

ln({e}^{4x})   =  \ln(11)

Recall that

\ln( {a}^{n} )  = n  \ln(a)

This means

4x \ln({e})   =  \ln(11)

Logarithm of the base is 1

4x (1)   =  \ln(11)

4x   =  \ln(11)

Divide both sides by 4

x=  \frac{ \ln(11)}{4} \\x=0.5995\\ x = 0.6

7 0
3 years ago
For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
A. B. C. D. E. Which expressions listed on the left are equivalent to ? Check all that apply. (Assume that a ≠ 0.) A B C D E
Neko [114]
The Answer Is .A,B,AND E
4 0
3 years ago
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