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ipn [44]
3 years ago
14

Help on question number 5. Please

Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:


Step-by-step explanation:

First you set up a porportion then times 15 ×60 divided by one hundred so it would be B

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Find the sum of the geometric sequence –3, 15, –75, 375, … when there are 9 terms and select the correct answer below.
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Sn=sum of the n terms of the geometric sequence.
a= the first term
r=the common ratio
n=numbers of terms.

Sn=a[(1-r^n)/(1-r)]

In this case:
a=-3
r=a₂/a₁=15/-3=-5
n=9

S₉=-3[(1-(-5)⁹) / (1-(-5))=
S₉=-3(1+1953125)/6)=
S₉=-3(1953126/6)=
S₉=-3(325521)
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What is the third quartile of this data set 21,24,25,28,2935,37,39,42
valentinak56 [21]

Answer:

Definitions:

The third quartile, denoted by Q3 , is the median of the upper half of the data set. This means that about 75% of the numbers in the data set lie below Q3 and about 25% lie above Q3;

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Step-by-step explanation:


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