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3 years ago

Im just be straight with y'all im clueless with this stuff :(

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

gotchu

i had to edit it on my laptop with the marker tool so be nice ik the handwriting suckssss

i'll write the points for you here tho:

(-2,-12)

(-1,-6)

(0,-3)

(1,-1.5)

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PLEASE PLEASE PLEASE HELP WILL GIVE BRAINLIEST 2/5 x + -6 + 7/15 x

Klio2033 [76]

Answer:

13x/15-6

Step-by-step explanation:

i used symlobab

5 0

3 years ago

Read 2 more answers

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are without replacement.

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

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3 years ago

Carl wants to give away 1/3(fraction) of his baseball card collection.

alexandr1967 [171]

Answer:

1/3 / 1/3

1/3 x 3/1

= 1

Step-by-step explanation:

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2 years ago

How do you simplify this problem?

Yuri [45]

1+tan^2(x) = sec^2(x)

sec^2(x) = 1/cos^2(x)

csc(-x) / 1/cos^2(x) =

cos^2(x) csc(-x)

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3 years ago

How much does 1 candy bar cost if 112 candy bars cost $78.00?

Alexxandr [17]

$0.70 per candy.
$78 divided by 112 gives $0.696, so by rounding off, you get 0.70

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3 years ago