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3 years ago

Anyone know this? Im doing a quiz right now. -11/14x (-1/17)

Mathematics

2 answers:

Alik [6]3 years ago

6 0

Answer:

11/238

Step-by-step explanation:

Hope this helps!

alekssr [168]3 years ago

4 0

The answer For your question is 11/238

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What do graphs of functions have in common?

Sedaia [141]

Answer:

x and y points on a plane

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3 years ago

Ming spent $18 on three colored markers,<br> How much did each marker cost?

ivanzaharov [21]

Answer:

Step-by-step explanation:

3+3+3+3+3+3=18

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3 years ago

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Which description compares the vertical asymptotes of function A and function B correctly?

neonofarm [45]

Answer:

Option B:

Function A has a vertical asymptote at x = 1

Function B has a vertical asymptote at x = -3

Step-by-step explanation:

A function f(x) has a vertical asymptote if:

$\lim_{x \to\\k^+}f(x) = \±\infty\\\\ \lim_{x \to\\k^-}f(x) = \±\infty$

This means that if there is a value k for which f(x) has infinity or a -infinity then x = k is a vertical asymptote of f(x). Therefore, the closer x to k approaches, the closer the function becomes to infinity.

We can calculate the asymptote for function A.

$\lim_{x \to \\1^+}(\frac{1}{x-1})\\\\ \lim_{x \to \\1^+}(\frac{1}{1^-1})\\\\ \lim_{x \to \\1^+}(\frac{1}{0}) = \infty\\\\and\\ \lim_{x \to \\1^-}(\frac{1}{x-1})\\\\\lim_{x \to \\1^-}(\frac{1}{0}) = -\infty$

Then, function A has a vertical asymptote at x = 1.

The asymptote of function B can be easily observed in the graph. Note that the function b is not defined for x = -3 and when x is closest to -3, f(x) approaches infinity.

Therefore x = -3 is asintota of function B.

Therefore the correct answer is option B.

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3 years ago

There are 3 cats in a room and no other creatures.

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Answer:

Step-by-step explanation:

since there are 1 tails per cat and 2 ears the ratio would be 1:2

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3 years ago

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What are the zeros of the function f(x) = x^4 - x² - 2?

vaieri [72.5K]

Answer:

$x= i\\\\ x = -i \\\\x=\sqrt 2\\\\x = -\sqrt 2$

Step-by-step explanation:

$~~~~~~x^4 -x^2 -2=0\\\\\implies x^2 \cdot x^2-2x^2 +x^2 -2 = 0\\\\\implies x^2(x^2 -2) +(x^2 -2) =0\\\\\implies (x^2 +1)(x^2 -2) = 0\\\\ \implies x^2 +1=0~~~~~~~~\text{or}~~~~~~~~~x^2 -2 = 0\\\\ \implies x = \pm\sqrt{-1}~~~~~~~\text{or}~~~~~~~~~~ x = \pm\sqrt 2\\\\\implies x= \pm i~~~~~~~~~~~~~\text{or}~~~~~~~~~ x= \pm\sqrt 2$

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2 years ago