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disa [49]
2 years ago
14

What is 9 + 10not a joke

Mathematics
2 answers:
Stells [14]2 years ago
8 0
19 .................
Sergio [31]2 years ago
4 0
19.  You can always use a calculator for a quick answer or if you are struggling try to figure it out on paper.  Good luck!
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If a new phone screen is 19.68 cm2 larger than your current phone screen, with the dimensions 6.1 cm and 10.8 cm, then the new p
lutik1710 [3]

Answer:

(C)85.56 cm², 12.4 cm

Step-by-step explanation:

The Area of the screen of the new phone is :

19.68cm² + Area of the current phone screen size

The current phone screen size has dimensions: 6.1 cm and 10.8 cm,

Area of the current phone screen size = 6.1 cm × 10.8cm

Area of the current phone screen size = 65.88 cm²

Hence, The Area of the screen of the new phone is :

19.68cm² + Area of the current phone screen size

= 19.68cm² + 65.88cm²

= 85.56 cm²

The new phone screen must have an area of 85.56cm², which is the product of 6.9 cm and ___

The is calculated as:

85.56cm²/6.9cm

= 12.4cm

Therefore, the new phone screen must have an area of 85.56cm², which is the product of 6.9 cm and 12.4cm

Option C is correct

7 0
2 years ago
Find the most general antiderivative of the function. (check your answer by differentiation. use c for the constant of the antid
katovenus [111]

The most general antiderivative of the given function g(t) is (8t + t³/3 + t²/2 + c).

The antiderivative of a function is the inverse function of a derivative.

This inverse function of the derivative is called integration.

Here the given function is: g(t) = 8 + t² + t

Therefore, the antiderivative of the given function is

∫g(t) dt

= ∫(8 + t² + t) dt

= ∫8 dt + ∫t² dt + ∫t dt

= [8t⁽⁰⁺¹⁾/(0+1) + t⁽²⁺¹⁾/(2+1) + t⁽¹⁺¹⁾/(1+1) + c]

= (8t + t³/3 + t²/2 + c)

Here 'c' is the constant.

Again, differentiating the result, we get:

d/dt(8t + t³/3 + t²/2 + c)

= [8 ˣ 1 ˣ t⁽¹⁻¹⁾ + 3 ˣ t⁽³⁻¹⁾/3 + 2 ˣ t⁽²⁻¹⁾/2 + 0]

= 8 + t² + t

= g(t)

The antiderivative of the given function g(t)is (8t + t³/3 + t²/2 + c).

Learn more about antiderivative here: brainly.com/question/20565614

#SPJ4

8 0
1 year ago
Using the expansion for the binomial: ( x^3 − y^4 )^9 :The coefficient for the 6th term is
Lelechka [254]

Answer:

-126

Step-by-step explanation:

For the binomial expression  (a-b)^{n} the coefficient of (r+1)^{th} term is given by {n \choose r} \times -1^{(r)}.

We have to find the coefficient of 6th term in the binomial expansion of

(x^{3}-y^{4})^{9}.

Hence n=9 and r=5

The coefficient of 6th term = {9 \choose 5} \times (-1)^{5}

                                             = -{9 \choose 5}

                                             = -126

8 0
2 years ago
Which of the following describes a positive correlation?
insens350 [35]

Answer:

First Choice: As the number of hours spent on homework increases, the tests scores increase.

Step-by-step explanation:

The definition of a positive correlation  is a relationship between two given variables, in which both variables are moving in the same direction. This can mean when one variable increases and the other variable increases, too, or one variable decreases and the other decreases as well.

The first choice is a positive correlation because both variables are changing (increasing) in the same direction. As you spend more time on homework, you're likely to get a higher test score.

The second choice cannot be a positive correlation because only one variable is having some kind of change (increasing). The doctor visits amount remains the same, so we can call this a zero-correlation relationship because the number of apples eaten yearly doesn't affect the amount of doctor visits. An apple a day keeps the doctor a way is just a proverb, not to be taken literally.

The third choice cannot be a positive correlation because the two variables are going different directions. Even though the number of times going to bed early is increasing, the number of times waking up late decreases, which is not moving in the same direction as the other variable.

The fourth choice cannot be a positive correlation because, similarly to the third choice, the two variables are going different directions. One variable is increasing, which is the amount of practice time. Meanwhile, the other variable is decreasing (going in the opposite direction), which is the number of games lost in a season.

6 0
3 years ago
Why is it mathematically legal to multiply 2 √ 2 by √ 2 √ 2 in order to rationalize the denominator?
Gala2k [10]
Well if you're referring to rationalizing \bf \cfrac{2}{\sqrt{2}}, which simply means, getting rid of the pesky radical at the bottom

well, it boils down to, hmm say... a quantity or even a polynomial, multiplied times 1, is itself, 2*1=2, 3*1 = 3, ducks*1 = ducks, spaghetti * 1 = spaghetti

or whatever * 1 = whatever
and the value of the multiplicand, doesn't change in anyway, is the same thing before and after the multiplication by 1

now....1 can also be a fraction  \bf \cfrac{2}{2}=1\qquad \cfrac{3}{3}=1\qquad \cfrac{1,000,000}{1,000,000}=1
\\\\\\
\cfrac{ducks}{ducks}=1\qquad \cfrac{spaghetti}{spaghetti}=1\qquad \cfrac{cheese}{cheese}=1
\\\\\\
\cfrac{\textit{the quick fox jumped}}{\textit{the quick fox jumped}}=1\qquad \cfrac{whatever}{whatever}=1

so.. when you're doing \bf \cfrac{2}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\iff \cfrac{2}{\sqrt{2}}\cdot1

and the value multiplicand doesn't change in any way

now, try this in your calculator  \bf \cfrac{2}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{2\sqrt{2}}{\sqrt{2^2}}\implies \cfrac{2\sqrt{2}}{2}\implies \sqrt{2}\\\\
-----------------------------\\\\
\textit{check how much is }\cfrac{2}{\sqrt{2}}\textit{ in your calculator}
\\\\\\
\textit{then check how much is }\sqrt{2}\textit{ in it}
6 0
3 years ago
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