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IgorLugansk [536]
2 years ago
6

Express the division expression as a fraction in simplest form. Then, rewrite the fraction as a mixed number.

Mathematics
2 answers:
Levart [38]2 years ago
6 0
14/4 is simplified to 7/2 and as a mixed number it would be 3 1/2
pav-90 [236]2 years ago
6 0

Step-by-step explanation:

14 ÷ 4 is the same as the corresponding fraction (because a fraction is nothing else than a mini-division) :

14/4 = 7/2

and 7 divided by 2 is 3 with a remainder of 1. that means 1 time 1/2 remains as fraction.

so, the mixed number is

3 1/2

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5/6k=-20 what is the correct answer ??
damaskus [11]
<span>5/6k=-20

k=-24

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4 0
3 years ago
Read 2 more answers
Can I have the answer to this question please
Crazy boy [7]

answer = 9c²d^8

(3cd^4)^2

=(3)^2 × c^2 × (d^4)^2

=9×c^2×d^8 ----law of indices (a^m)^n = a^mn

=9c²d^8

6 0
3 years ago
Which products result in a difference of squares? Check all that apply.(x – y)(y – x)(6 – y)(6 – y)(3 + xz)(–3 + xz)(y2 – xy)(y2
nikitadnepr [17]

1. (3 + xz)(–3 + xz)

2. (y² – xy)(y² + xy)

3. (64y2 + x2)(–x2 + 64y2)

Explanation

The difference of 2 squares is in the form (a+b)(a-c).

(3 + xz)(–3 + xz) = (3 + xz)(xz -3)

                           = (xz + 3)(xz - 3)

                          = x²y²-3xy+3xy-9

                          =x²y² - 3²

(y² – xy)(y² + xy) = y⁴+xy³-xy³-x²y²

                          = y⁴ - x²y²

(64y2 + x2)(–x2 + 64y2)= (64y²+x²)(64y²-x²)

                                      = 4096y⁴-64y²x²+64y²x²-x⁴

                                      = 4096y⁴ - x⁴

3 0
3 years ago
Rickey has 7 over 8 cup of cereal in a bowl. He then gave two 1 over 4 cups of cereal from his bowl to his little sister. Which
NeX [460]

Answer:

5/8 cup left

Step-by-step explanation:

7/8 - 1/4

1/4=2/8

7/8-2/8

5/8

5 0
2 years ago
The circle C has centre A(2,1) and passes through the point B(10,7). Find and equation for C
Semmy [17]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the centre
r - the radius

A(2,1) - \hbox{the centre} \\&#10;h=2 \\ k=1 \\ \\&#10;(x-2)^2+(y-1)^2=r^2 \\ \\&#10;\hbox{passes through B(10,7)} \\&#10;x=10 \\&#10;y=7 \\ \\&#10;(10-2)^2+(7-1)^2=r^2 \\&#10;8^2+6^2=r^2 \\&#10;64+36=r^2 \\&#10;r^2=100 \\ \\&#10;\hbox{the equation:} \\ \boxed{(x-2)^2+(y-1)^2=100}
7 0
3 years ago
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