Answer: I think it is
Step-by-step explanation:
Answer: 0.0548
Step-by-step explanation:
Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.
Let 
represents the sample mean GPA for each student.
Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:
![P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28%5Coverline%7BX%7D%3E3.42%29%3DP%28%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%3E%5Cdfrac%7B3.42-3.5%7D%7B%5Cdfrac%7B0.5%7D%7B%5Csqrt%7B100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28Z%3E%5Cdfrac%7B-0.08%7D%7B%5Cdfrac%7B0.5%7D%7B10%7D%7D%29%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%3DP%28Z%3E1.6%29%5C%5C%5C%5C%3D1-P%28Z%3C1.6%29%5C%5C%5C%5C%3D1-0.9452%3D0.0548)
hence, the required probability is 0.0548.
Answer:
- 2x + y = - 1 , so the B is correct.
Step-by-step explanation:
+ Because of "the line passing through the pair of points (2,3) and (5,9)", that means the line has the equation y = ax + b where a = (9-3)/(5-2)= 6/3= 2
+ So the equation is y = 2x + b.
+ Then we replace x= 2 and y= 3 into y = 2x + b for finding like:
3 = 2*2 + b or 3 = 4 + b, so we find b = 3 - 4 = - 1.
+ The equation of this line is y = 2x - 1 or in the form:
2x - y - 1 = 0 (or -2x + y = -1)
Have a good day!
Answer: I believe the answer is 0.1875. Must be a typo here, because...
Step-by-step explanation: parentheses first. (2+1)3%32=
After parentheses are taken out. 3x3%32= No exponents, so multiply or divide, whatever comes first.
6%32 is 0.1875
