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miv72 [106K]
3 years ago
7

The wettest April for Albuquerque, NM, was recorded in 1905. The amount was 1.2in more than the amount recorded for the second w

ettest April, in 2004. If the total rainfall for these two months was 7.2in, how much rain fell in April of each year?
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
The 1905 was 3.0 inches while 2004 was 4.2 inches since they are 1.2 apart and they add up to 7.2
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Please help me and make sure to show your work
irina1246 [14]
Answer: C 20

Explanation: Plug in 2 for k.

2^2 - (2-10) + 4(2) = 20
4 0
3 years ago
Read 2 more answers
Someone help me fast please
lions [1.4K]

Answer:

86

Step-by-step explanation:

<u>Perimeter of WXY = WSY+WRX+XY</u>

<em>--> WSY = SY x 2</em>

--> WSY = 16 x 2 = 32

<em>Since it is an isosceles triangle, WRX = WSY</em>

--> WRX = 32

<em>--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.</em>

<em>--> Solve it using the cos theta rule</em>

--> Angle = Angle X = 70°

    Hypotenuse = WRX = 32

    Adjacent = WA = ?

<em>--> Cos (Angle) = Adjacent/Hypotenuse</em>

    Cos (70) = WA/32

    WA = 10.9 rounded off to 11

--> WA=AY= 11

--> XY = WA + AY = 11+11 = 22

<em>--> Perimeter = WSY+WRX+XY</em>

    Perimeter = 32+32+22

    Perimeter = 86

Therefore, the perimeter of WXY is 86.

4 0
3 years ago
Please help me solve this practice SAT question!
lord [1]

Answer:

t=5

Step-by-step explanation:

∵ (t,17) lies on (x,y) plane y=x²-3x+7,t>0

∴ 17=t²-3t+7

t²-3t+7-17=0

t²-3t-10=0

t²-5t+2t-10=0

t(t-5)+2(t-5)=0

(t-5)(t+2)=0

t=5,-2

t>0

so t=5

6 0
3 years ago
A flying carpet flies 2.4 miles with the wind in the same amount of time it flies 1.4 miles against the wind. The wind speed is
Ainat [17]

Answer:

15.2~mph

Step-by-step explanation:

Let the time flown by the flying carpet be t. Then, we have that (2.4)/t=(1.4)/t+2*4.

We multiply both sides of the equation by t to get 2.4=1.4+8t.

We subtract 1.4 from both sides to get 1=8t.

We divide both sides of the equation by t=1/8.

We know that the speed of the flying carpet in still wind is the average of the rates of the speed of the flying carpet with the wind and against the wind.

The speed with wind is (2.4)/(1/8)=19.2mph.

The speed against wind is (1.4)/(1/8)=11.2mph.

The speed in still wind is (19.2+11.2)/2=(30.4)/2=15.2.

Therefore, the answer is \boxed{15.2~mph} and we're done!

4 0
3 years ago
After your first semester of college is over, you discover that the math department has changed textbooks (again) so the booksto
statuscvo [17]

Answer:

about 2 or 3

Step-by-step explanation:

heres what u do go onlie and put the books up for sale.

3 0
3 years ago
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