Someone pls help me solve this ;-;
1 answer:
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Answer:
(a)$67
(b)You are expected to win 56 Times
(c)You are expected to lose 44 Times
Step-by-step explanation:
The sample space for the event of rolling two dice is presented below
Total number of outcomes =36
The event of rolling a 5 or a 6 are:
Number of outcomes =20
Therefore:
P(rolling a 5 or a 6)
The probability distribution of this event is given as follows.
First, we determine the expected Value of this event.
Expected Value
Therefore, if the game is played 100 times,
Expected Profit =$0.67 X 100 =$67
If you play the game 100 times, you can expect to win $67.
(b)
Probability of Winning
If the game is played 100 times
Number of times expected to win
Therefore, number of times expected to loose
= 100-56
=44 times
The smallest y can be is y = -1. The largest it can be is y = 1. The value of y can be anything in between. The value of y is a real number.
Answer: Choice D) All real numbers between -1 and 1 including -1 and 1
Note: we can write that as
which in interval notation would look like ![[-1, 1]](https://tex.z-dn.net/?f=%5B-1%2C%201%5D%20)
. The square brackets tell us to include the endpoints.
Answer: Choice D) All real numbers between -1 and 1 including -1 and 1
Note: we can write that as