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Mademuasel [1]
3 years ago
15

Which equation is parallel to y = 2 and goes through the point (-6, 10)?

Mathematics
2 answers:
QveST [7]3 years ago
6 0

Answer:

y= 10

Step-by-step explanation:

y = 2 is a horizontal line

It goes through the points (-6,10)  

The y value is 10

y= 10

guajiro [1.7K]3 years ago
5 0

Answer:

y = 10

Step-by-step explanation:

Parallel to y = 2 is a horizontal line passing through (-6,10)

y = 10

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Simplify this algebraic expression completely 10y-3(y+5)
vodka [1.7K]

Answer:

7y - 15

Step-by-step explanation:

6 0
2 years ago
Match each pair of points to the equation of the line that is parallel to the line passing through the pointsB(5,2) and C(7,-5)Y
a_sh-v [17]

we will select each points and find equation of line

option-A:

points are B(5,2) and C(7,-5)

x1=5,y1=2 , x2=7 , y2=-5

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-5-2}{7-5}

m=-3.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=-3.5(x-5)

y=\frac{-7}{2}x+\frac{39}{2}...........Answer

option-B:

points are D(11,6) and E(5,9)

x1=11,y1=6 , x2=5 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-6}{5-11}

m=-0.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-6=-0.5(x-11)

y=\frac{-1}{2}x+\frac{23}{2}...........Answer

option-C:

points are F(-7,12) and G(3,-8)

x1=-7,y1=12 , x2=3 , y2=-8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-8-12}{3+7}

m=-2

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-12=-2(x+7)

y=-2x-2...........Answer

option-D:

points are H(4,4) and I(8,9)

x1=4,y1=4 , x2=8 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-4}{8-4}

m=1.25

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-4=1.25(x-4)

y=\frac{5}{4}x-1...........Answer

option-E:

points are J(7,2) and K(-9,8)

x1=7,y1=2 , x2=-9 , y2=8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{8-2}{-9-7}

m=-\frac{3}{8}

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=\frac{3}{8}(x-7)

y=\frac{3}{8}x-\frac{5}{8}...........Answer

option-F:

points are L(5,-7) and M(4,-12)

x1=5,y1=-7 , x2=4 , y2=-12

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-12+7}{4-5}

m=5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y+7=5(x-5)

y=5x-32...........Answer



7 0
3 years ago
Read 2 more answers
PLZ HURRY IT'S URGENT!!!!!
Arte-miy333 [17]

the ratio that is equal to 10:85 is 20:170 because if you multiply both sides by two you get 20:170

7 0
3 years ago
WILL MARK BRAINLIEST!!!
babymother [125]

Answer: -2

Step-by-step explanation:

To find the slope of the line , we will write the equation in the form:

y = mx + x

where:

m = slope

c = y - intercept.

To write 4x + 2y = 12   in this form , we will make y the subject of the formula.

Subtract 4x from both sides

2y = -4x + 12

Divide through by 2y = -2x + 6

Therefore :

slope = -2

8 0
3 years ago
What equation represents the line that passes through the points(6,-3) and (-4,-9)?
marysya [2.9K]
M = - 3 + 9 / 6 + 4
m = 6 / 10
m = 3/5

- 3 = 3/5 ( 6 ) + c
- 15 = 18 + 5c
5c = - 33
c = - 33/5
y = 3/5x - 33/5
8 0
3 years ago
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