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kondor19780726 [428]
2 years ago
10

If n(U) = 360, n(A) = 240, n(B) = 160, find the maximum value of

Mathematics
1 answer:
Ainat [17]2 years ago
5 0

Answer:

here is answer

Step-by-step explanation:

n(AUB) = n(A) + n(B) - n(AnB )

= 240 + 160 - n(A n B)

= 400 - n(AnB )

Since n(AnB) 20, so n(AUB) S 400

But n(U) = 360, so n(A U B)* 360

.. the maximum value of n(AUB) = 360.

When n(A U B) is maximum, n(AnB) will be minimum.

.. min. value of n(An B)

= n(A) + n(B) - Max, value of n(AUB)

= 240 - 160 - 360 = 40

Again, n(

A B) will be maximum when B C A.

..the max. value of n(

A B) = n(B) = 160

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{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

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{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

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{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

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{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

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