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3 years ago

I need help with this algebra question can someone explain the steps on how you solve it ?

Mathematics

2 answers:

katovenus [111]3 years ago

4 0

Answer:

Step-by-step explanation:

(5+√2)²

you distribute the ² in the ()

so 5²+√2²

5²=25

√2²=2 because the √ and ² cancel each other out and you get 2

so now you have

25+2

which equals

Goryan [66]3 years ago

3 0

Given expression:

(5 + $\sqrt{2}$ )²

Now let us solve this problem by simplifying it;

(5 + $\sqrt{2}$ )²:

the power implies the expression in the bracket should be repeated twice:

= (5 + $\sqrt{2}$ ) (5 + $\sqrt{2}$ )

Then expand the bracket by distribution;

= (5 x 5) + 5( $\sqrt{2}$ ) + 5( $\sqrt{2}$ ) + 2

= 25 + 10 $\sqrt{2}$ + 2

= 27 + 10 $\sqrt{2}$

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anzhelika [568]

Printer A prints for 10 minutes, so prints

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3 years ago

find the values of x and y that make these triangles congruent by the hl theorem x=2,y=3 x=-2,y=3x=3,y=2x=4,y=8

AnnyKZ [126]

Answer:

The correct option is x=3 , y=2

Step-by-step explanation:

According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

Now we will plug the value y+1 of equation 1 in equation 2.

2x+3 = 3y+3

2(y+1)+3=3y+3

2y+2+3=3y+3

2y+5=3y+3

Now combine the like terms:

5-3=3y-2y

2=y

y=2

Now plug the value y=2 in equation 1.

x=y+1

x=2+1

x=3

Thus the values of(x.y) are{(2,3)}

Therefore the correct option is x=3 , y=2 .....

3 0

3 years ago

Jana baked some muffins. After she served 13 of them to her friends for brunch, she had 17 left. How many muffins did she bake?

aleksley [76]

Answer:

Step-by-step explanation:

Add 13 served to 17 left over to get how many muffins she originally baked.

6 0

1 year ago

Read 2 more answers

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is: