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Wewaii [24]
3 years ago
7

I need help with that

Mathematics
2 answers:
alukav5142 [94]3 years ago
8 0
If i remember correctly.. it’s C, you cant have the X values repeating.
statuscvo [17]3 years ago
6 0
Letter c I think it is
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Y=sqrt(x)(8x-5) find the derivative
garri49 [273]

Answer:

\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}

General Formulas and Concepts:  <u> </u>

<u>Algebra I</u>  

  • Exponentials [Fractions] - Are radicals
  • Exponential Rule [Rewrite]: \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>  

Derivatives  

Derivative Notation  

Derivative of a constant is 0  

Basic Power Rule:  

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle y = \sqrt{x}(8x - 5)

<u>Step 2: Differentiate</u>

\displaystyle f(x) = \sqrt{x}, \ g(x) = (8x - 5)

  1. Product Rule:                                                                                                  \displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]
  2. Rewrite:                                                                                                           \displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]
  3. Basic Power Rule:                                                                                          \displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{1 - 1}
  4. Simplify:                                                                                                          \displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{0}
  5. Rewrite:                                                                                                           \displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8
  6. Multiply:                                                                                                           \displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}
  7. Rewrite:                                                                                                           \displaystyle y' = \frac{8x + 5}{2\sqrt{x}} + 8\sqrt{x}
  8. Add/Rewrite:                                                                                                   \displaystyle y' = \frac{24x - 5}{2\sqrt{x}}
3 0
3 years ago
PLEASE PLEASE PLEASE HELP ME Which of these lines has a slope of -3?
ikadub [295]
D. Is the one which has slope -3

It is because the point of it’s slopes are
( 0,0) and (1,-3)
So the slope will be

(Y2 - Y1)/(X2-X1)
Hence -3 is the slope of graph D.
5 0
3 years ago
Read 2 more answers
 can you help me solve the equation: 5m+3=18
shtirl [24]
5m+3=18\ \ \ \ \ |subtract\ 3\ from\ both\ sides\\\\5m=15\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{m=3}
5 0
4 years ago
Read 2 more answers
Define the mathematical base <br>And give an example
lyudmila [28]

Answer:

Answer below

Step-by-step explanation:

A base is the number of digits in a number system. For example in the decimal number system we use the 10 digits ( 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 ). So it has the base 10.

HOPE IT HELPED

6 0
3 years ago
If someone could help me!
daser333 [38]
The answer is choice C) All real numbers from 0 through 35.

The domain is the set of allowed inputs (x). The points on this graph have x coordinates that span from x = 0 to x = 35. Because x is time in minutes, we can have fractions of a minute (eg: x = 7.5 ---> 7 and a half minutes). So we won't just have integers. 
3 0
3 years ago
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