The initial length of the blue ribbon = 1.6 meters
Step-by-step explanation:
Here, according to the question:
The initial length of orange ribbon = 2 meters
Let us assume the initial length of blue ribbon = S meters
Now, the length of blue ribbon = (4/5) times the length of orange ribbon
x Length of Orange ribbon
or S = 1.6 meters
Hence, the initial length of the blue ribbon is 1.6 meters.
We are given
Vertical asymptotes:
Firstly, we will factor numerator and denominator
we get
We can see that (x-3) is common in both numerator and denominator
so, we will only set x+3 to 0
and then we can find vertical asymptote
Hole:
We can see that (x-3) is common in both numerator and denominator
so, hole will be at x-3=0
Horizontal asymptote:
We can see that degree of numerator is 2
degree of denominator is also 2
for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator
and we get
so, option-D............Answer
Answer:
x = 4 or x = -3
Step-by-step explanation:
Take square both the sides,
x² - x - 12 = 0
x² - 4x + 3x - 3*4 =0
x*(x - 4) + 3*(x - 4)= 0
(x- 4 )(x+3) =0
x -4 =0 or x + 3 = 0
x = 4 or x = -3