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marusya05 [52]
3 years ago
13

Solve the following system of equations by the substitution method.

Mathematics
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

The y-coordinate is y=-\frac{8}{13}

Step-by-step explanation:

Given equations are

5x=y+6\hfill (1)

2x-3y=4\hfill (2)

To solve the given equations by substitution method

From Equation (1) we can write x=\frac{y+6}{5}

Substitute the value x=\frac{y+6}{5} in equation (2) we get

2\times (\frac{y+6}{5})-3y=4

\frac{2}{5}(y+6)-3y=4

\frac{2y+12}{5}-3y=4

\frac{2y+12-15y}{5}=4

-13y+12=20

-13y=20-12

Therefore y=-\frac{8}{13}

Substitute the value of y=-\frac{8}{13} in equation (1) we get

5x=-\frac{8}{13}+6

x=-\frac{8-78}{-65}

=\frac{70}{65}

Therefore x=\frac{14}{13}

Therefore the y-coordinate is y=-\frac{8}{13}

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Answer:

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Step-by-step explanation:

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Answer:

((2 x^2 + 1)^2)/(x^2)

Step-by-step explanation:

Simplify the following:

(2 x + 1/x)^2

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Put each term in 2 x + 1/x over the common denominator x: 2 x + 1/x = (2 x^2)/x + 1/x:

((2 x^2)/x + 1/x)^2

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(2 x^2)/x + 1/x = (2 x^2 + 1)/x:

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Hint: | Distribute exponents over quotients in ((2 x^2 + 1)/x)^2.

Multiply each exponent in (2 x^2 + 1)/x by 2:

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