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NARA [144]
3 years ago
6

The equation for the horizontal line that contains the point E(3, –4)?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
The slope of a  horizontal line will have a value equal to 0: 
m=0
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

We have a point ( E(3,-4) ) and the slope of this line (m=0); therefore:y
y+4=0(x-3=
y+4=0
y=-4

Answer: the equation for the horizontal line that contains the point E, would be:
y=-4
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Explanation:
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The 1 added at the end means it was translated 1 unit up as well.

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3 years ago
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1. Observe problem

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Answer: -27/8

Step-by-step explanation:

\left(-\frac{1}{2}\cdot \:3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\quad \mathrm{if\:}n\mathrm{\:is\:odd}

\left(-\frac{1}{2}\cdot \:3\right)^3=-\left(\frac{1}{2}\cdot \:3\right)^3

=-\left(\frac{1}{2}\cdot \:3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

\left(\frac{1}{2}\cdot \:3\right)^3=\left(\frac{1}{2}\right)^3\cdot \:3^3

=-\left(\frac{1}{2}\right)^3\cdot \:3^3

=-\frac{1}{8}\cdot \:3^3

=-\frac{1}{8}\cdot \:27

=-\frac{27}{8}

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3 years ago
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alexdok [17]

Answer:

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