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3 years ago

PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRR

Mathematics

1 answer:

Paul [167]3 years ago

8 0

Answer:

Step-by-step explanation:

just cause

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Answer:

5. 8/6x + 2

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2 years ago

Keith works 8 hours per day for 5 per week. melba works 2,250 minutes each week. who spends more time at work

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Step-by-step explanation:

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3 years ago

Is y=7x-3 have a proportional relationship

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Answer:

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Step-by-step explanation:

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3 years ago

If you take a number, times by 7 then subtract 1. You get the same as if you took the number multiply the number by 5 then subtr

Irina-Kira [14]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

2 years ago