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2 years ago

A recipe calls for 2/3 of cup of milk for 11 cookies. How many cups of milk are needed to make 165 cookies?

Mathematics

2 answers:

Viefleur [7K]2 years ago

5 0

A is the correct answer

Explication:
165/11 = 15
2/3x 15 = 10

sukhopar [10]2 years ago

4 0

Answer:

the answerr issssss c cccccccccccccc

Step-by-step explanation:

You might be interested in

3 2/3+2.3 repeating

Dvinal [7]

Answer:

Step-by-step explanation:

2.3 repeating = 2 1/3

So 3 2/3 + 2 1/3

= 5 + 1

= 6.

8 0

3 years ago

Read 2 more answers

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

8 0

2 years ago

What is the quotient 1 5/8 ÷ -1 3/5

Shalnov [3]

Answer:

-1 1/64

Step-by-step explanation:

13/8 * - 5/8 = -65/64, or -1 1/64

I hope this helped, please mark Brainliest, thank you!!

5 0

2 years ago

Given that f(x)=x^2-4x -3 and g(x)=x+3/4 solve for f(g(x)) when x=9

SSSSS [86.1K]

Answer:

f(g(9)) = 945/16

Step-by-step explanation:

To find f(g(x)), you have to substitute g(x) wherever there is an x in f(x).

g(x) = x + 3/4

f(x) = x² - 4x - 3

f(g(x)) = (x + 3/4)² - 4(x + 3/4) - 3

f(g(x)) = x² + 3/2x + 9/16 - 4x + 3 - 3

f(g(x)) = x² - 5/2x + 9/16 + 3 - 3

f(g(x)) = x² - 5/2x + 9/16

Now, put a 9 wherever there is an x in f(g(x)).

f(g(9)) = (9)² - 5/2(9) + 9/16

f(g(9)) = 81 - 5/2(9) + 9/16

f(g(9)) = 81 - 45/2 + 9/16

f(g(9)) = 117/2 + 9/16

f(g(9)) = 945/16

7 0

2 years ago

NEED HELP ASAP!!! Will give brainliest!!!

Gekata [30.6K]

Answer:

1, 4/5,2/5

Step-by-step explanation:

y = 5x

Let y = 5

5 = 5x

Divide by 5

5/5 =5x/5

1=x

Let y=4

4 =5x

Divide by 5

4/5 =5x/5

4/5 =x

Let y=2

2 =5x

Divide by 5

2/5 =5x/5

2/5 =x

5 0

3 years ago