Answer:
d. ![x = 10](https://tex.z-dn.net/?f=x%20%3D%2010)
e. ![x=\sqrt[3]{\dfrac{15}{4}}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D%7B4%7D%7D)
Step-by-step explanation:
I've typed up my workings in MS Word and attached them (as it's very difficult to type this in the Brainly equation editor).
I've used the product, quotient and power log laws.
Product: ![log_a(x)+log_a(y)=log_a(xy)](https://tex.z-dn.net/?f=log_a%28x%29%2Blog_a%28y%29%3Dlog_a%28xy%29)
Quotient: ![log_a(x)-log_a(y)=log_a(\dfrac{x}{y})](https://tex.z-dn.net/?f=log_a%28x%29-log_a%28y%29%3Dlog_a%28%5Cdfrac%7Bx%7D%7By%7D%29)
Power: ![p\log_a(x)=log_a(x^p)](https://tex.z-dn.net/?f=p%5Clog_a%28x%29%3Dlog_a%28x%5Ep%29)
Answer:
I would say 2,3,4.
Step-by-step explanation:
I hope this helps and i hope this is the right answer
D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.
D+y1=y2 that drops -y1 for the right side but the left remains.
And that's your answer.
Answer:
The area of tarpaulin is 1315.63 ft^2.
Step-by-step explanation:
height, h = 20 feet
circumference, C = 102 feet
Let the radius is r.
Circumference, C = 2 x 3.14 x r = 102
r = 16.24 feet
Let the slant height is L.
![L = \sqrt{h^2 + r^2}\\\\L = \sqrt{20^2 + 16.24^2}\\\\L = 25.8 ft](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7Bh%5E2%20%2B%20r%5E2%7D%5C%5C%5C%5CL%20%3D%20%5Csqrt%7B20%5E2%20%2B%2016.24%5E2%7D%5C%5C%5C%5CL%20%3D%2025.8%20ft)
The curved surface area is
S = 3.14 x r x L
S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2
Answer:
step 3
Step-by-step explanation:
4*7=28
Not 26