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Julli [10]
3 years ago
13

Write an equivalent expression for each of the following. Express your answers in the form a + bi or a - bi

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

44 +14i

Step-by-step explanation:

(5 + i)(9 + i)

FOIL

first 5*9 = 45

inner: 9i

outer :5i

last: i*i = i^2 = -1

Add togheter

45 + 9i+5i -1

Combine like terms

44 +14i

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54) z(4z+7) =0
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Help ill give brainliest and a thank you and 5 star if correct
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Answer:

85%

Step-by-step explanation:

The discount is 15% which we can write as 0.15 and we multiply that by 30 to get the discount, which is $4.50. We subtract that from the original price; 30 to get $25.50 as the sale price. We want to find out what percent of 30 25.50 is, so we divide 25.50 and 30 to get 0.85. Multiply that by 100 to get 85%.

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Answer:

x=17

Step-by-step explanation

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alexandr402 [8]

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Step-by-step explanation:

3 0
3 years ago
The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
3 years ago
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