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MatroZZZ [7]
3 years ago
14

Please help with questions 7-12

Chemistry
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

negitive 5 or -5

Explanation

usally 12-7 = 5 but 7 is first so it you turn 5 to negitive 5

or -5

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4 years ago
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Suppose a liquid level from 5.5 to 8.6 m is linearly converted to pneumatic pressure from 3 to 15 psi. What pressure will result
wlad13 [49]

Answer:

a) P = 9.58 psi for  h=7.2 m

b) P=4.7 psi for h=5.94 m

Explanation:

Since the pressure Pon a static liquid level h is

P= p₀ + ρ*g*h

where p₀= initial pressure , ρ=density , g = gravity

then he variation of the liquid level Δh will produce a variation of pressure of

ΔP= ρ*g*Δh → ΔP/Δh =  ρ*g = ( 15 psi - 3 psi) /( 8.6 m - 5.5 m)  = 12/3.1 psi/m

if the liquid level is converted linearly

P = P₁ + ΔP/Δh*(h -h₁)

therefore choosing  P₁ = 3 psi and h₁= 5.5 m , for h=7.2 m

P = 3 psi  + 12/3.1 psi/m *(7.2 m -5.5 m) = 9.58 psi

then P = 9.58 psi for  h=7.2 m

for P=4.7 psi

4.7 psi = 3 psi  + 12/3.1 psi/m *(h -5.5 m)

h = (4.7 psi - 3 psi)/ (12/3.1 psi/m) + 5.5 m = 5.94 m

then P=4.7 psi for h=5.94 m

5 0
4 years ago
Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p
Butoxors [25]

Answer:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

BiO_3^-\rightarrow Bi^{3+}

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

(Bi^{5+}O_3)^-\rightarrow Bi^{3+}

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Then, we accommodate the waters to obtain:

3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-

Best regards!

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3 years ago
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3 years ago
you have two solid substances that look the same. what measurements would you take and what tests would you perform to determine
andreev551 [17]


The easiest way to go about this would be to check out their physical properties. Physical properties are those attributes of a substance or material that can be observed or measured without altering or changing the composition of that material.

So we can check out the following physical properties:

1. Color. Check if there is any difference in color.

2. Weight. If possible, take similar sized pieces of the two and note any difference in weight .

3. Texture. Are they smooth or rough to the touch?

4. Smell or odor. Check out any unique smell.

5. Solubility. Dissolve a bit of each in water and see how soluble each is.

6. Melting point. Carefully heat a piece of it and see if they will melt, and if so at what temperature.

7. Pliability. Can any of them bend, are they flexible?

8. Magnetism. Can the be attracted by a magnet?

9. Bouyancy . Can they float on water?

10. Electrical conductivity. using a battery and small torch bulb, find out if they can conduct an electric current.

These 10 physical tests can help differentiate between the two materials. There are  still many more that can  be safely carried out.

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