Answer:
10
Explanation:
The unbalanced combustion reaction is shown below as:-
On the left hand side,
There are 3 hydrogen atoms and 1 nitrogen atom and 2 oxygen atoms
On the right hand side,
There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms
Thus,
Right side, 
must be multiplied by 6 to balance hydrogen.
Left side, 
must be multiplied by 4 to balance hydrogen.
Also, Right side, 
is multiplied by 4 so to balance nitrogen.
Left side, 
must be multiplied by 5 to balance the whole reaction.
Thus, the balanced reaction is:-
Sum of Coefficient of product - 4 + 6 = 10
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
<h3>What is IUPAC convention?</h3>
IUPAC convention of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).
The name of the compound is written out with the substituents in alphabetical order followed by the base name (derived from the number of carbons in the parent chain).
Types of IUPAC Nomenclature of a few important aliphatic compounds:
- Alkane
- Alkene
- Alkyne
Example :
Ethane, which has 2 carbon atoms and 6 hydrogen atoms, with the molecular formula of = C₂H₆
Formation of alkyl group:
Methane (CH₄) Remove 1 hydrogen (H) convert to methyl (H₃-C-)
Example: Propyl (-CH₃ - CH₂ - CH₂ - )
According to the IUPAC convention alkyl substituents on a hydrocarbon chain should be listed in alphabetical without considering prefixes order.
Learn more about IUPAC convention, Here:
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<span>We can solve this problem by assuming that the decay of
cyclopropane follows a 1st order rate of reaction. So that the
equation for decay follows the expression:</span>
A = Ao e^(- k t)
Where,
A = amount remaining at
time t = unknown (what to solve for) <span>
Ao = amount at time zero = 0.00560
M </span><span>
<span>k = rate constant
t = time = 1.50 hours or 5400 s </span></span>
The rate constant should
be given in the problem which I think you forgot to include. For the sake of
calculation, I will assume a rate constant which I found in other sources:
k = 5.29× 10^–4 s–1 (plug in the correct k value)
<span>Plugging in the values
in the 1st equation:</span>
A = 0.00560 M * e^(-5.29 × 10^–4 s–1 * 5400 s )
A = 3.218 <span>× 10^–4 M (simplify
as necessary)</span>
6.022 x 10^23
I answered this already :)
