Calculate the molality of a 5.51 M ethanol (C2H5OH) solution whose density is 0.9349 g/mL
1 answer:
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<h2>Answers to the whole assignment:</h2>
**Check for proof photos at the bottom.**
**Answers are in bold.**
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If you decreased the volume of a sample of gas by a factor of three while maintaining a constant pressure, how would the absolute temperature of the gas be affected?
✔ it would decrease threefold
A gas at 300 K and 4.0 atm is moved to a new location with a temperature of 250 K. The volume changes from 5.5 L to 2.0 L. What is the pressure of the gas at the new location?
✔ 9.2 atm
What is the partial pressure of 0.50 mol Ne gas combined with 1.20 mol Kr gas at a final pressure of 730 torr?
✔ 215 torr
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How will the volume of a gas be affected if the pressure is tripled, but the temperature remains the same?
✔ it is decreased to one third of its original volume
Why might a rubber raft burst if it is left in the sun on a summer day?
✔ temperature increases, causing interior pressure to increase
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Complete the table by filling in the missing information.
✔ pressure, volume A
✔ temperature, moles of gas B
✔ Charles’s law C
✔ V = kT D
✔ temperature, pressure E
✔ P = kT F
✔ number of moles only G
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Match one graph shown at right to each of the gas laws named below.
Charles’s law
✔ d
Gay-Lussac’s law
✔ b
Boyle’s law
✔ e
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Left answers:
1.31 atm A
0.44 atm B
Right answers:
✔ decreases it
✔ decreases it
0.12 atm C
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<h2>Explanation:</h2>When decreasing a volume while maintaining the same pressure, the temperature will have to decrease. When volume decreases, particles get squished, increasing pressure. But when temperature decreases, particles move slower, decreasing pressure. The lowered temperature decreases pressure, but the decreased volume increases pressure, so pressure is able to stay constant.
About the 3 main gas laws covered in Edge:
- Charles's law says that under a constant pressure, when temperature increases, the volume increases, and vice versa. The equation for this law is V₁/T₁=V₂/T₂.
- Gay-Lussac’s law says that under a constant volume, when temperature increases, the pressure increases, and vice versa. The equation for this law is P₁/T₁=P₂/T₂.
- Boyle’s law says that under a constant temperature, when volume decreases, pressure increases, and vice versa. The equation for this law is P₁V₁=P₂V₂.
Note that P=pressure, V=volume, and T=temperature. When given a problem, plug in the given values into the correct spots and solve for the unknown value.
Here are photos of Edge. I hope this made your day a little easier.