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brilliants [131]
4 years ago
14

Lauren needs 3.6 meters of ribbon to make a bow. She

Mathematics
1 answer:
docker41 [41]4 years ago
5 0
The answer is 22.85
Hope this helps
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Find the perimeter. The shape consists of a square and a half circle. Solve
erastovalidia [21]
I got 12.28 inches in total, hope this helps

5 0
3 years ago
How many faces does a hexagonal prism have?
noname [10]
Hexagonal Prism have 8 faces in total.........
5 0
3 years ago
A museum offers a 2 hour guided group tour. For groups with fewer than 35 people the cost is $12.25 per
Rudik [331]

Answer:

The total refund that the museum owes the 11:00am group is $28.50

Step-by-step explanation:

$12.25*38 = $465.50

$11.50*38 = $437

Subtract: $465.50 - $437 = $28.50

5 0
3 years ago
Question 12 Multiple Choice Worth 1 points)
serg [7]

Answer:

y - 3x = -10

Step-by-step explanation:

Complete question

<em>Choose the equation below that represents the line passing through the point (2, -4) with a slope of 3</em>

The standard equation of a line in point-slope form is y-y0 = m(x-x0)

Given

x0 = 2

y0 = -4

alope m  = 3

Substitute

y - (-4) = 3(x - 2)

y + 4 = 3(x - 2)

y + 4 = 3x - 6

y - 3x = -6 - 4

y - 3x = -10

Hence the required equation is y - 3x = -10

3 0
3 years ago
Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)
Drupady [299]

Answer:

The equivalent will be:

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}

Let us solve the expression step by step to get the equivalent

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}

as

\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}      ∵ \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}

\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

=x^{2\cdot \frac{1}{7}}

=x^{\frac{2}{7}}

also

\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}         ∵  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}

\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

=y^{3\cdot \frac{1}{5}}

=y^{\frac{3}{5}}

so the expression becomes

\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)            ∵ \:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}

Thus, the equivalent will be:

\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)

Therefore, option 'a' is true.

5 0
3 years ago
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