The first 8 on the left in this number has a value of 800.
Answer:
I can't answer this unless you give more information to the question.
The answer is 509 ft^3
Formula:
V = πr^2h
V = 3.14 * 4.5^2 * 8
V = 3.14 * 20.25 * 8
V = 508.68 ft^3
508.68 rounded to the nearest whole number is 509
So the volume of the cylinder is 509 ft^3
Answer:
Choice A) 
.
Step-by-step explanation:
What are the changes that would bring 
to 
?
- Translate to the left by
unit, and - Stretch vertically (by a factor greater than .)
. The choices of listed here are related to :
- Choice A)
; - Choice B)
; - Choice C)
; - Choice D)
.
The expression in the braces (for example 
as in ) is the independent variable.
To shift a function on a cartesian plane to the left by 
units, add to its independent variable. Think about how 
, which is to the left of , will yield the same function value.
Conversely, to shift a function on a cartesian plane to the right by units, subtract from its independent variable.
For example, 
is unit to the left of . Conversely, 
is unit to the right of . The new function is to the left of . Meaning that should should add to (rather than subtract from) the independent variable of . That rules out choice B) and D).
- Multiplying a function by a number that is greater than one will stretch its graph vertically.
- Multiplying a function by a number that is between zero and one will compress its graph vertically.
- Multiplying a function by a number that is between
and zero will flip its graph about the -axis. Doing so will also compress the graph vertically. - Multiplying a function by a number that is less than will flip its graph about the -axis. Doing so will also stretch the graph vertically.
The graph of is stretched vertically. However, similarly to the graph of this graph , the graph of increases as increases. In other words, the graph of isn't flipped about the -axis. should have been multiplied by a number that is greater than one. That rules out choice C) and D).
Overall, only choice A) meets the requirements.
Since the plot in the question also came with a couple of gridlines, see if the points 
's that are on the graph of fit into the expression 
.
Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
