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inn [45]
3 years ago
8

Please help as soon as possible

Mathematics
1 answer:
Gemiola [76]3 years ago
8 0
I believe the answer is A, however, i'm not sure. You can try. I hope I helped in any way possible. 
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The average speed to go by car from home to college is 30 miles per hour. The average speed to go back home from college is 20 m
Levart [38]

Answer:

24 mph for both 60 miles and 40 miles.

Step-by-step explanation:

We need to find how long it takes to get to college and from it.

Speed x time (x) = Distance (60)

30x = 60

x=2

It takes two hours to get to college

20x = 60

x = 3

It takes 3 hours to get back. It's a total of 5 hours, 2 hours at 30mph and 3 at 20. Now we need to find the average

30+30+20+20+20=120

120/5= 24

The average speed for the round trip is 24.

To do the second part, we follow the same process, but replace 60 with 40 for distance.

30x=40

x= 1.33

20x=40

x=2

We can add the total distance and divide by total time to find the average.

The total distance is 80. Time is 3.33

80/3.33=24

The average speed is still 24.

3 0
3 years ago
How do I turn this 10(0j + 40 + 4j) into a verbal expression? <br> I NEED HELP!!!!1
egoroff_w [7]

Answer:

See below

Step-by-step explanation:

You could say "10 times the sum of 0j, 40, and 4j" because that is exactly what you are doing in the algebraic expression.

3 0
2 years ago
The registration period for the race is under way, and as the word is getting out, the number of participants registering is gro
Olin [163]

y = a(1 + r)ˣ

a = 15  "<em>initial" means what you started with on the first day</em>

r = 6   <em>the rate it increased is the slope ((\frac{21 - 15}{2 - 1})</em>

y = 15(1 + 6)ˣ

Answer: y = 15(7)ˣ

3 0
3 years ago
Can someone please help me please?
ycow [4]

Answer:

Step-by-step explanation:

3 0
3 years ago
Solve for x: −1 &lt; x + 3 &lt; 5
Art [367]

Answer:

B. −4 < x < 2

Step-by-step explanation:

−1 < x + 3 < 5

To make x the subject, subtract 3 across the inequality

−1 - 3 < x + 3 - 3 < 5 - 3

-4 < x < 2

8 0
3 years ago
Read 2 more answers
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