Which line is perpendicular to the line 3y=5x-1

2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7 not pemdas

antiseptic1488 [7]

60

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Step by Step Solution:

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "2.7" was replaced by "(27/10)". 8 more similar replacement(s)

STEP

1

:

27

Simplify ——

10

Equation at the end of step

1

:

27 62 93 12 62 93 12 27

(((——•——)-(——•——))+(——•——))-(——•——)

10 10 10 10 10 10 10 10

STEP

2

:

6

Simplify —

5

Equation at the end of step

2

:

27 62 93 12 62 93 6 27

(((——•——)-(——•——))+(——•——))-(—•——)

10 10 10 10 10 10 5 10

STEP

3

:

93

Simplify ——

10

Equation at the end of step

3

:

27 62 93 12 62 93 81

(((——•——)-(——•——))+(——•——))-——

10 10 10 10 10 10 25

STEP

4

:

31

Simplify ——

5

Equation at the end of step

4

:

27 62 93 12 31 93 81

(((——•——)-(——•——))+(——•——))-——

10 10 10 10 5 10 25

STEP

5

:

6

Simplify —

5

Equation at the end of step

5

:

27 62 93 6 2883 81

(((——•——)-(——•—))+————)-——

10 10 10 5 50 25

STEP

6

:

93

Simplify ——

10

Equation at the end of step

6

:

27 62 93 6 2883 81

(((——•——)-(——•—))+————)-——

10 10 10 5 50 25

STEP

7

:

31

Simplify ——

5

Equation at the end of step

7

:

27 31 279 2883 81

(((—— • ——) - ———) + ————) - ——

10 5 25 50 25

STEP

8

:

27

Simplify ——

10

Equation at the end of step

8

:

27 31 279 2883 81

(((—— • ——) - ———) + ————) - ——

10 5 25 50 25

STEP

9

:

Calculating the Least Common Multiple

9.1 Find the Least Common Multiple

The left denominator is : 50

The right denominator is : 25

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

2 1 0 1

5 2 2 2

Product of all

Prime Factors 50 25 50

Least Common Multiple:

50

Calculating Multipliers :

9.2 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

9.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

L. Mult. • L. Num. 837

—————————————————— = ———

L.C.M 50

R. Mult. • R. Num. 279 • 2

—————————————————— = ———————

L.C.M 50

Adding fractions that have a common denominator :

9.4 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

837 - (279 • 2) 279

——————————————— = ———

50 50

Equation at the end of step

9

:

279 2883 81

(——— + ————) - ——

50 50 25

STEP

10

:

Adding fractions which have a common denominator

10.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

279 + 2883 1581

—————————— = ————

50 25

Equation at the end of step

10

:

1581 81

———— - ——

25 25

STEP

11

:

Adding fractions which have a common denominator

11.1 Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1581 - (81) 60

——————————— = ——

25 1

Final result :

60

7 0

3 years ago

3/10 divided by 6/11

mylen [45]

Answer:

Hi, I love these types of questions. So, ima teach you how to find the answer. If your only looking for an answer, skip to the bottom. So, what your trying to find is the solution to 3/10 divided by 6/11. So, remember, copy, dot, flip.

Copy- Copy the equation- 3/10 6/11

Dot- Change the division sign to multiplication- 3/10 X 6/11

Flip- so, this is where it gets a bit tricky. You wanna flip the numerator and denominator on the second fraction- 3/10 X 11/6

now multiply across-

33/60

simplify

11/20

Your answer is 11/20

3 0

3 years ago

Yer has 2107 beads for making jewelry. If each necklace she makes needs 49 beads, how

9966 [12]

41 necklaces can be made using 2017 beads where 49 beads are used to make 1 necklace.

The total number of beads for making jewelry with Yer = 2017

Beads require to make 1 necklace = 49 beads

The number of necklaces that can be made using 2017 beads when 49 beads are required to make 1 necklace will be:

Number of necklace = 2017 / 49

Number of necklace = 41.16

That is 41 necklaces can be made using 2017 beads where 49 beads are used to make 1 necklace.

Therefore, 41 necklaces can be made using 2017 beads where 49 beads are used to make 1 necklace.

Learn more about Number here:

brainly.com/question/24644930

#SPJ9

5 0

2 years ago

Is x plus y equals 3, then 3 equals x plus y. what is the property

Oksanka [162]

Answer

associative property of addition.

7 0

4 years ago

Once again, Bob and John went to the candy store. Bob bought 5 pieces of fudge and 4 pieces of bubble gum for a total of $10.10.

Ket [755]

Answer:

The fudge is $1.3 and the bubble gum is $0.9

3 0

3 years ago

Read 2 more answers