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3 years ago

14

How do I do these 2 questions in the picture provided?

1 answer:

poizon [28]3 years ago

3 0

1) Arc Length, knowing Ф value, the central angle: 2π.R.(Ф/360°)

Length (Arc ACB) = 2π(8).(90/360) = 16π/4 = 4π
Perimeter ACBO = Length (Arc ACB) + OA + OB = 4π + 8 + 8
Perimeter ACBO = 4π+16 (answer)

2) Area of a circular sector = πR².(Ф/360°)
Area of right triangle AOB = AO.AB/2 = 8x8/2 = 64/2 = 32 (Needed later)
Area ACBO = π.8².(90°/360°) = 64.π.1/4 = 16π, BUT WE NEED the area limited between the arc and the chord:
Area bounded by cord and arc)=Area sector (ACB0) - Area right triangle AOB
Area bounded by cord and arc= 16π- 64/2.

Area bounded by cord and arc= 16π- 32 (answer D)

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Find the simplest interest. principal = $870 interest rate = 3% time = 9 months

JulsSmile [24]

Answer: $889.58

Step-by-step explanation:

⇒<u>Equation:</u>

A = P(1 + rt)

Turn 3% into decimal and you get 0.03, then 9 months/ 12 months = 0.75 years.

<h2><u>WORK ↓</u></h2>

⇒A = 870(1 + (0.03 × 0.75)) = 889.575

⇒A = $889.58

* Hopefully this helps:) Mark me the brainliest:) !!!!

8 0

3 years ago

There are 14 books on a shelf. 6 of these books are new.

Alexxandr [17]

a) 8:14

b) 6:8

yeah its telling me I'm short of words

3 0

3 years ago

Read 2 more answers

Can you answer this one please

creativ13 [48]

Answer:

50⁰

Step-by-step explanation:

Since j and k are parallel lines cut by two transversals,

2+3+5=180⁰ <em>(</em><em>Allied</em><em> </em><em>angles</em><em>)</em>

We are given 2(60⁰) and 5(70⁰)

so,

60⁰+3+70⁰=180⁰

60+70=130

130⁰+3=180⁰

Bring the 130⁰ to the R.H.S

3=180⁰-130⁰

Therefore,

3=50⁰

6 0

2 years ago

Need help immediately

vekshin1

The answer is 6*square rooted*2

3 0

3 years ago

My Notes The displacement from equilibrium of an oscillating weight suspended by a spring is given by y(t) = 1 4 cos(5t) where y

ikadub [295]

Answer:

y(0) = 0.25 feet

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

Step-by-step explanation:

We are given the following information in the question:

The displacement from equilibrium of an oscillating weight suspended by a spring =

$y(t) = \displaystyle\frac{1}{4} \cos(5t)$

where y is the displacement in feet and t is the time in seconds.

Here, cos is in radians.

1) t = 0

$y(0) = \displaystyle\frac{1}{4} \cos(5(0)) = \frac{1}{4} \cos(0) = \frac{1}{4}(1) = \frac{1}{4}$

y(0) = 0.25 feet

2) t = $\frac{1}{4}$

$y(\displaystyle\frac{1}{4}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{4})) = \frac{1}{4} \cos(1.25) = \frac{1}{4}(0.31532236) =0.07883059$

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

3) t = $\frac{1}{2}$

$y(\displaystyle\frac{1}{2}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{2})) = \frac{1}{4} \cos(2.5) = \frac{1}{4}(-0.80114362) = -0.200285905$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

The negative sign indicates the opposite direction of displacement.

3 0

3 years ago