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ruslelena [56]
3 years ago
14

How do I do these 2 questions in the picture provided?

Mathematics
1 answer:
poizon [28]3 years ago
3 0
1) Arc Length, knowing Ф value, the central angle: 2π.R.(Ф/360°)

Length (Arc ACB) = 2π(8).(90/360) = 16π/4 = 4π
Perimeter ACBO = Length (Arc ACB) + OA + OB = 4π + 8 + 8
Perimeter ACBO = 4π+16 (answer)

2) Area of a circular sector = πR².(Ф/360°)
    Area of right triangle AOB = AO.AB/2 = 8x8/2 = 64/2 = 32 (Needed later)
Area ACBO = π.8².(90°/360°) = 64.π.1/4 = 16π, BUT WE NEED the area limited between the arc and the chord:
Area bounded by cord and arc)=Area sector (ACB0) - Area right triangle AOB
Area bounded by cord and arc= 16π- 64/2.

Area bounded by cord and arc= 16π- 32 (answer D)

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What is the measure of the third angle in the similar triangles below?
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Answer:

65°

Step-by-step explanation:

All triangles equal 180 degrees. So just subtract the other values.

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Answer:

Its the last one: a translation 2 units right and 4 units down.

Step-by-step explanation:

To get from point E (1,3) to E' (3-1) you add 2 units to the x coordinate since the x-axis goes from left to right  and moving to the right means its positive and then you subtract 4 from the y coordinate since the y axis is going up and down and when you move -4 points you move down 4 points. You do this to every other point get the new figure.

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3 years ago
Lines L and M are parallel. Lines t^1 and t^2 are transversals. What is m<1 if m<4=65*? Justify your answer. (Ps- there is
Diano4ka-milaya [45]
The complete question in the attached figure

we know that
m∡4=65°
m∡4=m∡2---------> by internal alternate angles
m∡5=m∡3---------> by internal alternate angles

m∡1=180°-m∡2---------> 180°-65°--------> m∡1=115°

the answer is 
m∡1=115°

3 0
3 years ago
What is -64/5 as a mixed number
Slav-nsk [51]
Your answer to the question:

-12 4/5

And then decimal form:

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8 0
2 years ago
7/8 - 5/12 ayudaaa por favor es para mañana​
RUDIKE [14]
7/8 = 21/24
5/12 = 10/24

21/24-10/24 = 11/24
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