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2 years ago

Find the midpoint of the segment with the following endpoints. (10, 7) (2, 1)

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

7 0

Answer:

(6,4)

Step-by-step explanation:

Midpoint=((x1+x2)/2 ,(y1+y2)/2)

((10+2)/2 ,(7+1)/2)

(6,4)

x1=10

x2=2

y1=2

y2=1

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What is the length of ac help pls

Lelu [443]

Answer:

x=2

Step-by-step explanation:

This is an isosceles triangle you can tell by the two congruent/equal angles

angle A is congruent/equal to angle C by definition the two sides will be equal.

x-4=3x-8

1. get all you x's on one side. by subtracting x from both sides you don't have to deal with dividing by negatives later on.

x-x-4=3x-x-8

-4=2x-8

now you want to get x by itself so add 8 to both sides

4= 2x

x is still not by itself so divide both sides by 2

x=2

6 0

2 years ago

Select the correct answer

soldi70 [24.7K]

Answer:

The Expression h(-7) represents the output of h corresponding to the input of -7

Step-by-step explanation:

7 0

2 years ago

The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/

VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

$A = \frac{1}{2}bh$ (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

$\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)$

We can find the base by solving equation (1) for b:

$b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm$

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

$2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)$

$\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min$

Therefore, the base is decreasing at 2 cm/min.

I hope it helps you!

7 0

2 years ago

What is the answer of this question

zvonat [6]

The right answer is x^2-1.

EXPLANATION:

To be a polynomial, the power of each term must be a whole number.

Hope it will be helpful to you...

Good luck on your assignment

~pragya

6 0

3 years ago

The triangle below is equilateral. Find the length of side x to the nearest tenth.

Gemiola [76]

Answer:

$\sqrt{\frac{15}{2} }$ or 2.738

Step-by-step explanation:

Let’s just look at the triangle on the top with the $\sqrt{10}$ on the top and x on the bottom. (Basically the top half to the equilateral triangle)

There is a small square in the bottom right corner, which indicates that this triangle is a right triangle. This means that we can use the Pythagorean Theorem: $a^{2} +b^{2} =c^{2}$

We know that \sqrt{10} is our hypotenuse, and therefore our c in our equation. Let’s say that x=a in our equation. Therefore we are left to find b. However, b is half the length of the side of the original equilateral triangle. An equilateral triangle means that all three sides are the same length. Therefore our side would also be \sqrt{10} units long. However we know that b is half of that value, so b= $\frac{1}{2}(\sqrt{10})$ or $\frac{\sqrt{10} }{2}$