Given circle with radius of 5cm. Find out (a) diameter (b) perimeter (c) area
1 answer:
Answer:
(1) 10
(2) 10π
(3) 25π
Step-by-step explanation:
We are given the radius of the circle which is halfway through a circle. The radius of this circle is 5.
We are required to find the diameter, perimeter, and area using the given data we have been provided with.
Let's start:
#1: Diameter
To find diameter use formula:
After substituting we have:
After calculating, we have found that the diameter of the circle is 10.
#2: Perimeter
The perimeter can also be known as the circumference of a circle as they both measure the outline.
To find circumference use formula:
After substituting we have:
Convert to a decimal and round it to the nearest tenth and we have:
⇒ 31.4159265359
⇒ 31.4
After calculating, we have found that the perimeter (or circumference of the circle is 10π or 31.4 (Rounded to the nearest tenth in decimal form).
#3: Area
To find area use the formula:
After substituting we have:
Convert to a decimal and round it to the nearest tenth and we have:
⇒ 78.5398163397
⇒ 78.6
After calculating we have found that the area of the circle is either 25π or 78.6 (rounded to the nearest tenth).
After finding all the required information, we have now completed the answer.
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The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.
Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives
... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)
... 2x +z = -4 . . . . simplified
Likewise, we can add 3 times the second equation to the first to cancel y in that sum.
... 3(5x +y -4z) +(2x -3y +z) = 3(41) + (-1)
...15x +3y -12z +2x -3y +z = 123 -1
...17x -11z = 122 . . . . simplified
Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:
... 11(2x +z) +(17x -11z) = 11(-4) +122
...22x +17x = 78 . . . . . . simplify a little bit
... x = 78/39 = 2 . . . . . . divide by 39
From above, we find
... z = -4 -2x = -4 -2·2 = -8
... y = 41 -5x +4z = 41-5(2) +4(-8) = 41 -42 = -1
The solution is (x, y, z) = (2, -1, -8).
_____
The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.
Check the picture below.
