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densk [106]
4 years ago
5

True or False. Explain your answer. csc^-1[csc(-pi/4)]=-pi/4 sec[sec^-1(sqrt3)]=sqrt3

Mathematics
2 answers:
boyakko [2]4 years ago
7 0
Property of inverse functions:
f(f^{-1}(x)) = x \\  \\ f^{-1}(f(x)) = x

Therefore the answer to both is True.
Korolek [52]4 years ago
5 0

Answer:

True

Step-by-step explanation:

Given : Expression \csc^{-1}[\csc(-\frac{\pi}{4})]=-\frac{\pi}{4} and \sec[{\sec^-1}(\sqrt3)]=\sqrt3

To find: The given expression are true or false?

Solution :

In the given expression,

Applying Inverse trigonometric functions,

i.e, f(f^{-1}x)=x

or \csc^{-1} (\csc x)=x\\\csc(\csc^{-1} x)=x

and this true for all trigonometric functions.

So, if apply in the given expression the resultant we get is true.

\csc^{-1}[\csc(-\frac{\pi}{4})]=-\frac{\pi}{4} is true

and \sec[{\sec^-1}(\sqrt3)]=\sqrt3 is true

Therefore, The given expressions are true.                

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V125BC [204]

Answer:

baahsuslskissisudjxnxnx

6 0
2 years ago
Perform the indicated operation. Show all necessary work.
kvv77 [185]

Answer:

b is the answer ;)) ........................

6 0
3 years ago
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Find the missing terms in the equation so that it is true. b (3x−5)^2=(? + ?? +25)
igor_vitrenko [27]

Answer:

9x^2 and -30x

Step-by-step explanation:

Basically, what we want to do is expand out (3x - 5)^2, which is the same as (3x - 5)(3x - 5).

Use FOIL (first, outer, inner, last):

- the first terms are 3x and 3x, so multiply those together: 3x * 3x = 9x^2

- the outer terms are 3x and -5, so multiply those: 3x * (-5) = -15x

- the inner terms are -5 and 3x, so multiply those: (-5) * 3x = -15x

- the last terms are -5 and -5, so multiply those together: (-5) * (-5) = 25

Add all these together:

9x^2 + (-15x) + (-15x) + 25

9x^2 - 30x + 25

The missing terms are thus 9x^2 and -30x.

7 0
3 years ago
Read 2 more answers
Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w
Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1497, \sigma = 322

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1520 - 1497}{322}

Z = 0.07

Z = 0.07 has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

P = 0.4721*0.4721 = 0.2229

22.29% probability that both of them scored above a 1520

8 0
3 years ago
5.55 as a fraction or mixed number in simplest form
laila [671]
Well the first 5 in 5.55 will stay 5 and .55 is equal to 55/100 but divided by 5 equals 11/20 so ur answer is 5 55/100 or
5 11/20
3 0
3 years ago
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