Answer:
b is the answer ;)) ........................
Answer:
9x^2 and -30x
Step-by-step explanation:
Basically, what we want to do is expand out (3x - 5)^2, which is the same as (3x - 5)(3x - 5).
Use FOIL (first, outer, inner, last):
- the first terms are 3x and 3x, so multiply those together: 3x * 3x = 9x^2
- the outer terms are 3x and -5, so multiply those: 3x * (-5) = -15x
- the inner terms are -5 and 3x, so multiply those: (-5) * 3x = -15x
- the last terms are -5 and -5, so multiply those together: (-5) * (-5) = 25
Add all these together:
9x^2 + (-15x) + (-15x) + 25
9x^2 - 30x + 25
The missing terms are thus 9x^2 and -30x.
Answer:
22.29% probability that both of them scored above a 1520
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.
So



has a pvalue of 0.5279
1 - 0.5279 = 0.4721
Each students has a 0.4721 probability of scoring above 1520.
What is the probability that both of them scored above a 1520?
Each students has a 0.4721 probability of scoring above 1520. So

22.29% probability that both of them scored above a 1520
Well the first 5 in 5.55 will stay 5 and .55 is equal to 55/100 but divided by 5 equals 11/20 so ur answer is 5 55/100 or
5 11/20