Answer:

Step-by-step explanation:
since
,

Answer:

Step-by-step explanation:
Given
See attachment
Required
Determine the measure of 
.
So, we have:

Where:


Substitute these values in the above equation.


Collect Like Terms:


Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
7w + 4h + 10w + 15h - 2w - 2h
= 15w + 17h
X+y=31.5
x-y=5.25
add 2 equations
x+y+x-y=31.5+5.25
2x=36.75
x=18.375
y=31.5-18.375=13.125
check : 18.375+13.125=31.5, 18.375-13.125=5.25
so
Answer:
18.375 and 13.125