Question

Which statement describes the translation of y = − one over two (x − 2)2 − 2 from standard position

Answer 1

The standard position of a function is y = ax^n + bx^n-1 + ... k where a, b and k are all constants. In this case, the problem gives 

y = − one over two (x − 2)2 − 2
Translating numerically,
y = [-1/2(x-2)^2 ] -2 
2(x-2)^2 y = -1 -2(2*(x-2)^2)
2(x-2)^2 y= -1 -4(x^2-4x+4)
y = (-4x^2 + 16x -17) /(2(x-2)^2)