22) D. 5 miles
23) E
24) C. 4:30
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Correlation Coefficient (r) = 0.989
alph=0.05
Number of observations (n) = 8
determine if there is a linear correlation between chest size and weight.
Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.
What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.
r^2 = square of the correlation Coefficient
r^2 = 0.989^2 = 0.978121
Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.
Answer:
independent variable = number of laps;
dependent variable = number of dollars
Step-by-step explanation:
If we were to put this information into a slope-intercept form equation, the equation would be: y = 5x (dollars raised = 5 dollars per lap walked). In this case, we are going to use the variables l and d instead of x and y, respectively. The equation instead of being y = 5x, it is going to be d = 5l. In the slope-intercept form X will always be the independent variable and y the dependent variable, because the number we get for Y totally depends on what you plugged in for X. In this equation, l is the independent variable (the number of laps she walks) and d is the dependent variable (number of dollars).
