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ladessa [460]
3 years ago
7

Which number rounds to 4.3 when rounded to the nearest tenth?

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

it is the same 4.3

Step-by-step explanation:

this numbers didn't add one number when you round(0,1,2.3.4)

this numbers(5,6,7,8,9), you add one number when you add

4.3 (the three is the tenth)and no number after it so its stell the same

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Alex Ar [27]

Medical practitioners recommend losing around 365 pounds or 730 pounds per year.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Medical practitioners recommend losing around 1–2 pounds (0.5–0.9 kg) per week.

Hence for a year:

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Medical practitioners recommend losing around 365 pounds or 730 pounds per year.

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3 0
2 years ago
PLSSS RNNN<br> -5 + x = 10<br> x = 5<br> x = 10<br> x = -15<br> x = 15
Tema [17]
X = 15

Add 5 to each side
10 + 5 = 15
3 0
2 years ago
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Priya ran 1 ½ miles today, and Tyler ran 3 ¾ miles today. How many times the length of Tyler's run was Priya's run?
krek1111 [17]
Answer:
2.5
Step-by-step explanation:
6 0
2 years ago
PLZ HELP SOLVE: -4 &lt; k + 3 &lt; 8
vaieri [72.5K]
Hope this was what you’re looking for ^.^

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3 0
3 years ago
If x = a cosθ and y = b sinθ , find second derivative
Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

\dfrac{\mathrm d^2y}{\mathrm dx^2}

Compute the first derivative. By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}

We have

y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta

x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta

and so

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta

Now compute the second derivative. Notice that \frac{\mathrm dy}{\mathrm dx} is a function of \theta; so denote it by f(\theta). Then

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}

By the chain rule,

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}

We have

f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta

and so the second derivative is

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta

4 0
3 years ago
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